<h3>
Answer: b = 4 and c = 7.</h3>
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Explanation:
Comparing y = x^2+bx+c to y = ax^2+bx+c, we see that a = 1.
The vertex given is (-2,3). In general, the vertex is (h,k). So h = -2 and k = 3.
Plug those three values into the vertex form below
y = a(x-h)^2 + k
y = 1(x-(-2))^2 + 3
y = (x+2)^2 + 3
Then expand everything out and simplify
y = x^2+4x+4 + 3
y = x^2+4x+7
We see that b = 4 and c = 7.
Answer:
3,304
Step-by-step explanation:
Answer:
-35/4
Step-by-step explanation:
If <em>X</em> is uniformly distributed on the interval (0, 12), then its PDF is
or simply
and the zero-elsewhere case is assumed.
Whether you include 0 and 12 in the domain is irrelevant, since the probability that <em>X</em> = 0 or <em>X</em> = 12 are both zero.
Answer:
2x+6
Step-by-step explanation:
