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Misha Larkins [42]
2 years ago
7

le="\sf\large\green{\underbrace{\red{Question*}}}:" alt="\sf\large\green{\underbrace{\red{Question*}}}:" align="absmiddle" class="latex-formula">
\huge{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red}Factorize}}}}
{y}^{2}  - 3y - 4y + 12
9 {x}^{2}  - 12x + 4
​
Mathematics
1 answer:
Kaylis [27]2 years ago
5 0
<h3><u>Part A</u></h3>

\sf \rightarrow  y^2 - 3y - 4y +12

factor the common term 'y' and '-4'

\sf \rightarrow  y(y - 3) - 4(y - 3)

collect into groups

\sf \rightarrow  (y- 4)(y - 3)

<h3><u>Part B</u></h3>

\sf \rightarrow  9x^2 - 12x + 4

middle term split

\sf \rightarrow  9x^2 - 6x - 6x+ 4

factor the common term '3x' and '-2'

\sf \rightarrow  3x(3x - 2) -2( 3x-2)

collect into groups

\sf \rightarrow  (3x -2)( 3x-2)

simplify the following

\sf \rightarrow  (3x -2)^2

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Answer:

<h2><em>(</em><em>4</em><em>,</em><em>5</em><em>)</em></h2>

<em>sol</em><em>ution</em><em>,</em>

<em>A</em><em>(</em><em>2</em><em>,</em><em>7</em><em>)</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>></em><em> </em><em>(</em><em>X1,</em><em>y1</em><em>)</em>

<em>B</em><em>(</em><em>6</em><em>,</em><em>3</em><em>)</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>></em><em>(</em><em>x2</em><em>,</em><em>y2</em><em>)</em>

<em>now</em><em>,</em>

<em>ab = ( \frac{x1 + x1}{2}  \: , \frac{y1 + y2}{2} ) \\  =  (\frac{2 + 6}{2}  \: , \frac{7 + 3}{2} ) \\  = ( \frac{8}{2}  \:,  \frac{10}{2} ) \\  = (4 ,\: 5)</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>

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3 years ago
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