Tim has 56 more postcards than Paul.
Step-by-step explanation:
Total postcards boys have = 280
Let,
x = Paul's postcards
y = Shawn's postcards
z = Tim's postcards
According to given statement;
x + y + z = 280 Eqn 1
Eqn 2
Eqn 3
Putting value of y from Eqn 3 in Eqn 2
Eqn 4
Putting value of x and y from Eqn 4 and Eqn 3 in Eqn 1
![\frac{8}{15}z+\frac{4}{5}z+z=280\\\\\frac{8z+12z+15z}{15}=280\\\\\frac{35z}{15}=280\\\\](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B15%7Dz%2B%5Cfrac%7B4%7D%7B5%7Dz%2Bz%3D280%5C%5C%5C%5C%5Cfrac%7B8z%2B12z%2B15z%7D%7B15%7D%3D280%5C%5C%5C%5C%5Cfrac%7B35z%7D%7B15%7D%3D280%5C%5C%5C%5C)
Multiplying both sides by ![\frac{15}{35}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B35%7D)
![\frac{15}{35}*\frac{35}{15}z=280*\frac{15}{35}\\z=120](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B35%7D%2A%5Cfrac%7B35%7D%7B15%7Dz%3D280%2A%5Cfrac%7B15%7D%7B35%7D%5C%5Cz%3D120)
Putting z=120 in Eqn 3
![y=\frac{4}{5}*120\\y=96](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B4%7D%7B5%7D%2A120%5C%5Cy%3D96)
Putting y=96 in Eqn 2
![x=\frac{2}{3}*96\\x=64](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B2%7D%7B3%7D%2A96%5C%5Cx%3D64)
Difference of Tim and Paul = 120-64 = 56
Tim has 56 more postcards than Paul.
Keywords: linear equation, substitution method
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