Answer:
see explanation
Step-by-step explanation:
(a)
Given
2k - 6k² + 4k³ ← factor out 2k from each term
= 2k(1 - 3k + 2k²)
To factor the quadratic
Consider the factors of the product of the constant term ( 1) and the coefficient of the k² term (+ 2) which sum to give the coefficient of the k- term (- 3)
The factors are - 1 and - 2
Use these factors to split the k- term
1 - k - 2k + 2k² ( factor the first/second and third/fourth terms )
1(1 - k) - 2k(1 - k) ← factor out (1 - k) from each term
= (1 - k)(1 - 2k)
1 - 3k + 2k² = (1 - k)(1 - 2k) and
2k - 6k² + 4k³ = 2k(1 - k)(1 - 2k)
(b)
Given
2ax - 4ay + 3bx - 6by ( factor the first/second and third/fourth terms )
= 2a(x - 2y) + 3b(x - 2y) ← factor out (x - 2y) from each term
= (x - 2y)(2a + 3b)
Answer:
Should be D.
I don't know why it won't let me respond with under 20 characters.
Answer: (-1/5, 2/5)
Step-by-step explanation:
See the photo for explanation and work.
Standard form:
5,098,000
Scientific notation.
1) only 1 digit should be before the decimal point.
5.098000
2) only non-zero number must be part of the coefficient. the rest are included in the base of 10.
5.098 x 10^6 Choice D.
Exponent is the number of times the decimal moved from its original placement to its place after the 1st digit.
