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1 year ago

Can you please help me with this two questions

Mathematics

1 answer:

Natali [406]1 year ago

3 0

Answer:

2) d. 60°

3) a. AB

Step-by-step explanation:

Question 2

ΔABC and ΔCDA are congruent because:

they are both right triangles

they share one side (AC)

their hypotenuse are parallel (marked by the arrows)

This means the corresponding side lengths and angles are equal.

Therefore,

∠CDA = ∠ABC

⇒ x = 60°

Question 3

The hypotenuse is the longest side of a right triangle - the side opposite the right angle (the right angle is shown as a small square).

Therefore, the hypotenuse of ΔABC is the line AB.

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Round fraction as a decimal round three decimals place 6/13

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Round fraction as a decimal: 6/13=.462 that's the answer

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3 years ago

PLEASE HELP

Harlamova29_29 [7]

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3 years ago

Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From

maksim [4K]

Answer:

The 95% CI for the difference of means is:

$-155.45 \leq \mu_1-\mu_2 \leq -44.55$

Step-by-step explanation:

The question is incomplete:

"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size: 4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

$M_d=M_1-M_2=200-300=-100$

The standard deviation can be estimated as:

$\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45$

The degrees of freedom are:

$df=n_1+n_2-2=10+4-2=12$

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

$M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55$