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Ilya [14]
3 years ago
15

A train leaves the station at time = 0. Traveling at a constant speed, the train travels 330 kilometers in 3 hours. Answers part

s a and b. A. Write a function that relates the distance traveled d to time t. The function that relates the distance traveled d to the time is.
Mathematics
1 answer:
amid [387]3 years ago
5 0

Answer:

The function that relates the distance traveled d to the time t is

f(t) = 110t, where d = f(t)

Step-by-step explanation:

From the question, we were told that the train is At a constant speed, the train travels 330 kilometers in 3 hours

We were told to write function that relates the distance traveled d to the time t, we can do this by writing a linear equation with those functions

Since we are told that the train travels 330 kilometers in 3 hours, then we can say the train travel (330/3) kilometers in 1 hour which means it travel 110 kilometers in 1 hour

Then d= 110t---------------eqn(1)

If if t = 0, then d = 0, as well since at t=0 the train is at the station

At t = 1 then d = 110.

From equation (1) d can be replaced by f(t) then we have

f(t) = 110t----------------eqn(2)

Now we replace d by f (t), because d = f t):

f(t) = 120t

Therefore, The function that relates the distance traveled d to the time is f(t) = 120t

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Read 2 more answers
If events A and B are mutually exclusive, P(A or B) = 0.5, and P(B) = 0.3; then what is P(A)?
11Alexandr11 [23.1K]

Answer:

P(A) = 0.2

Step-by-step explanation:

We have that:

P(A) = P(a) + P(A \cap B)

In which P(a) is the probability of a but not b and P(A \cap B) is the probability of both A and B.

By the same logic, we have that:

P(B) = P(b) + P(A \cap B)

Also

P(A or B) is

P(A \cup B) = P(a) + P(b) + P(A \cap B)

Events A and B are mutually exclusive

This means that P(A \cap B) = 0

P(B) = 0.3 = P(b)

P(A \cup B) = P(a) + P(b) + P(A \cap B)

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P(A) = P(a) + P(A \cap B) = 0.2 + 0 = 0.2

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