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goldenfox [79]
3 years ago
14

Two math classes took the same quiz. The scores of 10 randomly selected students from each class are listed below. Sample of Cla

ss A: 75, 80, 60, 90, 85, 80, 70, 90, 70, 65 Based on the Medians of the scores for each class, what inference would you make about the quiz scores of all the students in Class A compared to all the students in Class B? Explain your reasoning to justify your answer
Mathematics
1 answer:
baherus [9]3 years ago
6 0
Since the median of 77.5 for class A is less than the median of 90 for class B, we can conclude that Class B is better prepared for the quiz than Class A.
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Fofino [41]

Answer:

In the attachment

Step-by-step explanation:

<, > - dots line

≤, ≥ - solid line

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>, ≥ - shading to the right

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8 0
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The sales tax rate is 3%. If Jeanette buys a robot priced at $233.00, how much tax will she<br> pay?
wolverine [178]

Answer:

The answer is $6.99 in tax, the new total is $239.99

Step-by-step explanation:

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4 years ago
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Anni [7]

Answers:

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=====================================================

The given info is:

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From that, we can use the pythagorean trig identity to find that cos(theta) = -5/13. Keep in mind that cosine is negative in quadrant II.

Now use the trig identity below to compute cos(2theta)

\cos(2\theta) = \cos^2(\theta)-\sin^2(\theta)\\\\\cos(2\theta) = \left(\frac{-5}{13}\right)^2-\left(\frac{12}{13}\right)^2\\\\\cos(2\theta) = \frac{25}{169}-\frac{144}{169}\\\\\cos(2\theta) = \frac{25-144}{169}\\\\\cos(2\theta) = -\frac{119}{169}\\\\

Other options you could use are these identities

\cos(2\theta) = 2\cos^2(\theta)-1\\\\

or

\cos(2\theta) = 1-2\sin^2(\theta)\\\\

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Maksim231197 [3]

1)a=0

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