Answer:
This implies that software firms
can develop upgrades with a lower cost and less risk than they can develop a new product.
MCKibben argues that the inhabitable planet is shrinking because:
- Consistently higher temperatures will likely make certain areas uninhabitable
- Desertification will reduce the amount of harvestable land
- Coastlines are being lost to sea level rise.
<h3>What is Shrinking?</h3>
This is the process in which an object or place becomes smaller as a result of various activities.
The most suitable options which explains why the planet is shrinking is as a result of a reduction in the areas in which humans can live as a result of the factors mentioned above.
Read more about Planet here brainly.com/question/11157969
Google Android OS is correct
Answer:
What is legal and ethical
Explanation:
Legal standards are based on law written, it tells us what we should do and what we is forbidden.
Ethical standards are based on human rights and wrongs
Answer:
The printout of the program is 33
Explanation:
Given the code as follows:
- int[][] values = {{3, 4, 5, 1}, {33, 6, 1, 2}};
- int v = values[0][0];
- for (int row = 0; row < values.length; row++)
- for (int column = 0; column < values[row].length; column++)
- if (v < values[row][column])
- v = values[row][column];
-
- System.out.print(v);
The code above will find the largest value from the two-dimensional array and print it out.
The logic of finding the largest value is as follows:
- Create a variable, <em>v</em>, to hold the largest number (Line 2). At the first beginning, we simply set the value from the first row and first column (values[0][0]) as our current largest value.
- Next, we need to compare our current largest value against the rest of the elements in the two dimensional array.
- To make the comparison, we need a two-layers for loops that will traverse through every row and column of the array and compare each of the element with the current largest value (Line 3-6).
- If the current largest value, v, is smaller than any element of the array, update the <em>v</em> to the latest found largest value (Line 5-6).
- After completion of the for-loop, the v will hold the largest number and the program will print it out (Line 8).