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2 years ago

What is the solution to the inequality.

Mathematics

1 answer:

Novosadov [1.4K]2 years ago

7 0

Answer:

a. x<7 and x>-7

Step-by-step explanation:

√x²<√49

-7<x<7 hope this helps

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Which graph shows y=2⌈x⌉−3?

umka2103 [35]

Answer: C

Step-by-step explanation:

5 0

2 years ago

Without using technology, describe the end

victus00 [196]

Answer:

Up on the left, up on the right

Step-by-step explanation:

The given function is:

$f(x)=3x^{4}+8x^{2}-22x+43$

The degree of f(x) is 4 i.e. an even degree and the leading coefficient i.e. coefficient with highest powered variable is positive in sign.

The graph of a function with even degree always open on same side from both ends. This depends on the sign of leading coefficient what will be the direction of both ends. The positive sign indicates upward opening and negative sign indicates downward opening.

Since, the leading coefficient of f(x) is positive, it will open towards up from both right and left side. So, the correct option is the fourth option.

7 0

3 years ago

A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is

insens350 [35]

Answer:

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

Step-by-step explanation:

A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is less than 0.16.

This means that the null hypothesis is:

$H_{0}: p \geq 0.16$

Testing this hypothesis, means that the alternate hypothesis is:

$H_{a}: p > 0.16$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.16 is tested at the null hypothesis:

This means that $\mu = 0.16, \sigma = \sqrt{0.16*0.84}$

In a sample of 200 graduates, 24 students have a GPA of 3.00 or below.

This means that $n = 200, X = \frac{24}{200} = 0.12$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.12 - 0.16}{\frac{\sqrt{0.16*0.84}}{\sqrt{200}}}$

$z = -1.54$

Pvalue:

The pvalue is the probability of finding a sample mean above 0.12, which is 1 subtracted by the pvalue of z = -1.54.

Looking at the z-table, z = -1.54 has a pvalue of 0.0618

1 - 0.0618 = 0.9382

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

6 0

3 years ago

Fr.ee points and offering brainliest for the best reply<br> and what is 1 + 1?<br> 25 points

nikitadnepr [17]

Answer:

2, your most gracious highness, superior leader of the Northern hemisphere

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Help based offf order of operations please help

JulijaS [17]

Answer:

The answer for :

$h. \: \: \: \frac{5}{6}$

$i. \: \: \: \frac{35}{32}$

$k. \: \: \: \frac{-29}{20}$

$l. \: \: \: \frac{13}{15}$

Step-by-step explanation:

Question h:

$\frac{2}{3} + ( \frac{1}{3} \times \frac{1}{2} )$

$= \frac{2}{3} + \frac{1}{6}$

$= \frac{2 \times 2}{3 \times 2} + \frac{1}{6}$

$= \frac{4}{6} + \frac{1}{6}$

$= \frac{5}{6}$

Question i:

$\frac{7}{8} + \frac{1}{4} \times ( \frac{3}{2} - \frac{5}{8} )$

$= \frac{7}{8} + \frac{1}{4} \times ( \frac{3 \times 4}{2 \times 4} - \frac{5}{8} )$

$= \frac{7}{8} + \frac{1}{4} \times ( \frac{12}{8} - \frac{5}{8} )$

$= \frac{7}{8} + (\frac{1}{4} \times \frac{7}{8} )$

$= \frac{7}{8} + \frac{7}{32}$

$= \frac{7 \times 4}{8 \times 4} + \frac{7}{32}$

$= \frac{28}{32} + \frac{7}{32}$

$= \frac{35}{32}$

Question k:

$\frac{3}{4} - ( \frac{12}{7} \div \frac{12}{21} ) + \frac{4}{5}$

$= \frac{3}{4} - ( \frac{12}{7} \times \frac{21}{12} ) + \frac{4}{5}$

$= \frac{3}{4} - \frac{3}{1} + \frac{4}{5}$

$= \frac{3 \times 5}{4 \times 5} - \frac{3 \times 20}{1 \times 20} + \frac{4 \times 4}{5 \times 4}$

$= \frac{15}{20} - \frac{60}{20} + \frac{16}{20}$

$= - \frac{29}{20}$

Question l:

$\frac{5}{2} \times ( \frac{2}{3} - \frac{1}{5} ) - ( \frac{2}{5} \div \frac{4}{3} )$

$= \frac{5}{2} \times ( \frac{2 \times 5}{3 \times 5} - \frac{1 \times 3}{5 \times 3} ) - ( \frac{2}{5} \times \frac{3}{4} )$

$= \frac{5}{2} \times ( \frac{10}{15} - \frac{3}{15} ) - \frac{3}{10}$

$= (\frac{5}{2} \times \frac{7}{15}) - \frac{3}{10}$

$= \frac{7}{6} - \frac{3}{10}$

$= \frac{7 \times 5}{6 \times 5} - \frac{3 \times 3}{10 \times 3}$

$= \frac{35}{30} - \frac{9}{30}$

$= \frac{26}{30}$

$= \frac{13}{15}$

8 0

3 years ago