Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
Answer:
Step-by-step explanation: dont work sorry
Answer:
12
Step-by-step explanation:
The smaller triangle seems to have dilated and formed the larger triangle. So, let's find the factor of increase.
9 / 3 = 3, so 3 is the factor of increase.
Now we need to do 4 x 3 = 12
So, ? = 12
<em>Hope that helps!</em>
<em>-Sabrina</em>
Answer:
True
Step-by-step explanation:
0 . 0 0 0
whole Tenths Hundredths Thousandths
Yes because if you put any number as “x” you will always get the same answer.
