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1 year ago

How many points marked on this graph are solutions?

Mathematics

1 answer:

FinnZ [79.3K]1 year ago

5 0

Answer:

2 points are solutions

Step-by-step explanation:

A solution is a value that makes the equation true, meaning the points fall on the line. For example, the point (0,1) is on the line, which means that for the equation, when x=0, y=1. This also applies for a second point, which is about (-3.5,-1.5).

Hope this helps! :)

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Organize your data and find the rate of change.

LuckyWell [14K]

A .E is 7 inches for the left arm
E is 8 1/2 inches for the left foot
the inputs look like the length of the arm (ie x) the outputs are the length of the foot
rate of change=change in y change in x use the data you gathered or this equation they give you = 0.860 • + 3.302

B. find the difference in y, then the difference in x, then divide (y over x) to get the slope
8-7/7 1/2-6 1/2 = 1/1 =1

C.you plug in any (x,y) point you used to find the slope
Solve for B
y = mx+b y = 1*x + b 7.5 = 1*8 + b b =
7.5 - 8 = -0.5
y = x - 0.5

Hope this helps

8 0

3 years ago

Can anyone help me I don’t understand plz

Citrus2011 [14]

There we have an information of two functions $g(t)\, and \, h(t)$

Using this two functions $g(t)\, and \, h(t)$ , we need to find the composition of functions (h\circ g)(t).

The composition of two functions h and g is the new function , by performing g first and then performing h.

$(h\circ g)(t)=h(g(t))$

$g(t)=3(t+1)$

$h(t)=2t$

Composition of h and g (t) = $(h\circ g)(t)$

$=h(g(t))$

First plugin the value of $g(t)=3(t+1)$

$h(g(t))=h(3(t+1))$

$=h(3t+3)$

We know that $h(t)=2t$ , we need to find h(3t+3),

That is, to replace t by 3t+3,

$=2(3t+3)$

Now distribute 2 into 3t+3,

$=6t+6$

Now plug in $t=-6,$

$h(g(-6))=6(-6)+6$

$=-36+6 \\ =-30$

Thus the solution is (D). $h(g(-6))=-30.$

5 0

3 years ago

Read 2 more answers

Graph the following two lines.

irina [24]

Answer:( 2 , 1 ) is a solution

Step-by-step explanation:

6 0

2 years ago

1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.

german

Answer:

Step-by-step explanation:

To write the form of the partial fraction decomposition of the rational expression:

We have:

$\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}$

Using partial fraction decomposition to find the definite integral of:

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx$

By using the long division method; we have:

$x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }$

$- 2x^3 -16x^2-40x$

$x+ 20$

So;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}$

By using partial fraction decomposition:

$\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}$

$= \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}$

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now; we have to relate like terms on both sides; we have:

A + B = 1 ; 2A - 10 B = 20

By solvong the expressions above; we have:

$A = \dfrac{5}{2}$ $B = \dfrac{3}{2}$

Now;

$\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}$

Thus;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}$

Now; the integral is:

$\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx$

$\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}$

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0

2 years ago

What is the volume of the spear w/t a radius of 3cm options 3,6,9,36

hram777 [196]

$\bf \textit{volume of a sphere}\\\\
V=\cfrac{4\pi r^3}{3}\quad 
\begin{cases}
r=radius\\
-----\\
r=3
\end{cases}\implies V=\cfrac{4\pi (3)^3}{3}$

6 0

2 years ago