Answer:
the slope of both lines are the same.
Step-by-step explanation:
Given the following segment of the Quadrilateral EFGH on a coordinate Segment FG is on the line 3x − y = −2,
segment EH is on the 3x − y = −6.
To determine their relationship, we can find the slope of the lines
For line FG: 3x - y = -2
Rewrite in standard form y = mx+c
-y = -3x - 2
Multiply through by-1
y = 3x + 2
Compare
mx = 3x
m = 3
The slope of the line segment FG is 3
For line EH: 3x - y = -6
Rewrite in standard form y = mx+c
-y = -3x - 6
Multiply through by-1
y = 3x + 6
Compare
mx = 3x
m = 3
The slope of the line segment EH is 3
Hence the statement that proves their relationship is that the slope of both lines are the same.
Answer:
2(3 + 8k)
Step-by-step explanation:
given : 6+16k
note that the GCF of 6 and 16 is 2, hence we can factor 2 out of the expression
6+16k
= (2)(3) + (2)(8k)
= 2(3 + 8k)
Answer:
Step-by-step explanation:
Given that in a recent poll 1 of 1000 American adults, the number saying that exercise is an important part of daily life was 753.
Sample proportion = 
To find 90% confidence interval we must find std error of proportion first
As per central limit theorem, sample proportion will follow a normal distribution with mean = 0.753
Std error of proportion= 
90% Z critical value = 1.645
Margin of error = 1.645*0.01363 = 0.0224
Confidence interval lower bound = 0.753-0.0224=0.731
Upper bound = 0.775
Answer:
The probability that the page will get at least one hit during any given minute is 0.9093.
Step-by-step explanation:
Let <em>X</em> = number of hits a web page receives per minute.
The random variable <em>X</em> follows a Poisson distribution with parameter,
<em>λ</em> = 2.4.
The probability function of a Poisson distribution is:

Compute the probability that the page will get at least one hit during any given minute as follows:
P (X ≥ 1) = 1 - P (X < 1)
= 1 - P (X = 0)

Thus, the probability that the page will get at least one hit during any given minute is 0.9093.
The answer to 75 squared is 5,625.