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galben [10]
2 years ago
10

PLZ help ASAP!!! I will mark Brainliest!

Mathematics
2 answers:
GuDViN [60]2 years ago
6 0

Answer:

C

Step-by-step explanation:

x=60

60

60+30=90

60-30=30

60+90+30=180

Blababa [14]2 years ago
3 0

Answer:

The Answer is : 60, 90, 30

Step-by-step explanation:

The sum of an angle in a triangle is 180'

        x + (x + 30) + (x - 30) = 180'

        x + x + 30 + x - 30 = 180'

collect like terms

        3x + 30 - 30 = 180'

        3x = 180'

         x = \frac{180'}{3}

         x = 60

So therefore, where x = 60

      x = 60

      x + 30 = 60 + 30 = 90

      x - 30 = 60 - 30 = 30

The Answer is : 60, 90, 30

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eduard

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Two trains leave the same station at the same time, but are headed in opposite directions. One train travels at 70 mph and the o
uranmaximum [27]

Let

x--------> the time in hours

y-------> the distance in miles

we know that

The speed is equal to

Speed=\frac{distance}{time}

in this problem

Speed=\frac{y}{x}

y=(Speed)*x

<u>Equation First Train</u>

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Rewrite the form In exponential form:<br> Log100 = x
andrey2020 [161]

Answer:

10^x=100

Step-by-step explanation:

You know how subtraction is the <em>opposite of addition </em>and division is the <em>opposite of multiplication</em>? A logarithm is the <em>opposite of an exponent</em>. You know how you can rewrite the equation 3 + 2 = 5 as 5 - 3 = 2, or the equation 3 × 2 = 6 as 6 ÷ 3 = 2? This is really useful when one of those numbers on the left is unknown. 3 + _ = 8 can be rewritten as 8 - 3 = _, 4 × _ = 12 can be rewritten as 12 ÷ 4 = _. We get all our knowns on one side and our unknown by itself on the other, and the rest is computation.

We know that 3^2=9; as a logarithm, the <em>exponent</em> gets moved to its own side of the equation, and we write the equation like this: \log_3{9}=2, which you read as "the logarithm base 3 of 9 is 2." You could also read it as "the power you need to raise 3 to to get 9 is 2."

One historical quirk: because we use the decimal system, it's assumed that an expression like \log1000 uses <em>base 10</em>, and you'd interpret it as "What power do I raise 10 to to get 1000?"

The expression \log100=x means "the power you need to raise 10 to to get 100 is x," or, rearranging: "10 to the x is equal to 100," which in symbols is 10^x=100.

(If we wanted to, we could also solve this: 10^2=100, so \log100=2)

6 0
2 years ago
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