You could easily do that yourself, with a pencil, and about the same amount of time it took you to post the question here.
If you go through and try them . . . 1/1, 1/2, 1/3, 1/4, 1/5 . . . etc., you'll find
that the thirds, sixths, sevenths, and ninths produce repeating decimals.
The oneths, tooths, fourths, fifths, eighths, and tenths don't.
Answer:
the number would be 11
Step-by-step explanation:
8 · x - 3 = 64
________ _ (divide both sides by 8)
8 8
x - 3 = 8
+ 3 + 3
x = 11
(check:
11 - 3 = 8
8 x 8 = 64 )
x= -4 because 1.4 times -4=- 5.6 and 2.6 times -4=-10.4 and when we add to numbers postive or negative numbers it stays positive or negative depnding on the problem and 10.4 + 5.6 + 16 however becuase both were negative the answers stays negative making the answer _ 16 and it says 1.4x+2.6x=-16 so the correct answer is x= -4
If we dialate a function we are just changing what the graph looks like by a stretch or a compression, the function really doesn't change. If a function before the dilation, then it is a function after the dilation. The opposite is also true.
F(x) = 18-x^2 is a parabola having vertex at (0, 18) and opening downwards.
g(x) = 2x^2-9 is a parabola having vertex at (0, -9) and opening upwards.
By symmetry, let the x-coordinates of the vertices of rectangle be x and -x => its width is 2x.
Height of the rectangle is y1 + y2, where y1 is the y-coordinate of the vertex on the parabola f and y2 is that of g.
=> Area, A
= 2x (y1 - y2)
= 2x (18 - x^2 - 2x^2 + 9)
= 2x (27 - 3x^2)
= 54x - 6x^3
For area to be maximum, dA/dx = 0 and d²A/dx² < 0
=> 54 - 18x^2 = 0
=> x = √3 (note: x = - √3 gives the x-coordinate of vertex in second and third quadrants)
d²A/dx² = - 36x < 0 for x = √3
=> maximum area
= 54(√3) - 6(√3)^3
= 54√3 - 18√3
= 36√3.
