The points I chose and their connection are shown in the attached graph.
By looking at the problem, we can tell that 466 dollars is 2/3 of the original price. therefore, 1/3 of it would be 233 so the original price is 699
3.50 / 2.50
multiply by 10
35/25
divide by 5
7/5
The combination shows that the different groups of three that can be chosen for a newspaper photo is 10.
<h3>How to calculate the value?</h3>
From the information, Joyce, Karen and Paula are starters on their school basketball team.
The information is to illustrate the different groups of three that can be chosen for a newspaper photo.
This will be:
= 5!/3!(5 - 3)!
= 5!/3!2!
= (5 × 4 × 3 × 2 × 1)/(3 × 2 × 2)
= 20/2
= 10
There will be 10 groups.
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Answer:
Each ticket it 9$
Step-by-step explanation:
3 by 3 is 3 times 3
3 times 3 is 9
$81/9 is 9