Answer:
7 mins
Step-by-step explanation:
Current speed of Joes Car = 65.5 mph
We have to find the time interval for which the car exceeded the speed limit of 55 mph.
While, we are given that the speed of the car was constantly increasing, hence the speed over all increased from the limit of 55 mph = 65.50-55.00 = 10.50 mph
We are also given that Joes car was increasing speed at a constant rate of 1.50 mph for every passing minute. Hence
1.50 mph is increased in 1 minute
1 mph will be increase in 
minutes
Hence
10.50 mph will be increased in 
minutes
Hence joes car was exceeding the limit of 55 mph for 7 minutes.
Answer:
greatest 9776410 smallest 1046779
Step-by-step explanation:
in smallest we cannot write 0 first because 0 has no units
A = 30,000 - 2000m where A=altitude and m = number of minutes
After 5 minutes A ( altitude) = 30,000 - 2000(5) = 20,000 feet
Let q and n represent the number of quarters and nickels respectively.
q=3n and .05n+.25q=1.6 These are the conditions in mathematical terms.
To solve, use the value of q from the first equation in the second equation to get:
.05n+.25(3n)=1.6 carry out indicated multiplication on left side
.05n+.75n=1.6 combine like terms on left side
.8n=1.6 divide both sides by .8
n=2, since q=3n
q=6
So Peggy had 2 nickels and 6 quarters.
Area of lower rect + area of upper + 4 * sides rect areas
lower = upper rect
2 * rect1 + 4 * rect2
Area = 2 * 6 * 11 + 2 * 11 * 9 + 2 * 9 * 6 = 438 ft^2
or simply just take 2 ( and multiply each two sides.
