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Sergio [31]
3 years ago
6

Give the place and value. Then round the number to that place 49.21

Mathematics
1 answer:
kotegsom [21]3 years ago
5 0
If you need to round to the nearest whole number it will be 49. If it’s round to the nearest tenth it will be 49.2
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What is the GCF of 14 and 21
n200080 [17]
Hey there the answer is, 

<span>The Greates Common Factor (GCF) is:   7
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3 years ago
The annual snowfall in city Ais 43.9 inches. This is 13.5 inches more than four times the snowfall in city B. Find the annual sn
Jlenok [28]

Answer:

24.475

Step-by-step explanation:

1st Divide: 43.9÷4=10.975

2nd Add 13.5: 10.975+13.5=24.475

--------------------------------------------------------------------

Hope this helps you out :)

7 0
3 years ago
Simplify (-8z+4) + (7z-7)
Karo-lina-s [1.5K]

Answer:

1. -1z-3

2. 4x+2

3. -y+11

4. 7a-22

Step-by-step explanation:

Not too sure about the last one

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3 years ago
Which number has two lines of symmetry?<br><br> 101<br> 619<br> 33<br> 18 <br> not multiple answer
podryga [215]

Answer:

The number is 33

Step-by-step explanation:

8 0
2 years ago
20 points Return to questionItem 4Item 4 20 points Police records in the town of Saratoga show that 13 percent of the drivers st
Sladkaya [172]

Answer:

a) 0.1423

b) 0.2977

c) 0.56

Step-by-step explanation:

For each driver stopped for speeding, there are only two possible outcomes. Either they have invalid licenses, or they do not. The probability of a driver having an invalid license is independent from other drivers. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

13 percent of the drivers stopped for speeding have invalid licenses.

This means that p = 0.13

14 drivers are stopped

This means that n = 14

(a) None will have an invalid license.

This is P(X = 0)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.13)^{0}.(0.87)^{14} = 0.1423

(b) Exactly one will have an invalid license.

This is P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{14,1}.(0.13)^{1}.(0.87)^{13} = 0.2977

(c) At least 2 will have invalid licenses.

Either less than 2 have invalid licenses, or at least 2 does. The sum of the probabilities of these events is decimal 1. Mathematically, this is

P(X < 2) + P(X \geq 2) = 1

We want P(X \geq 2)

So

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1) = 0.1423 + 0.2977 = 0.44

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.44 = 0.56

8 0
3 years ago
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