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dmitriy555 [2]
1 year ago
13

This month is October. Which month will 2451 months be later?

Mathematics
1 answer:
amid [387]1 year ago
8 0

Answer:

January

Step-by-step explanation:

The month October is the 10th month,

there is 12 months in a year

2451 / 12 = 204.25

0.25 of a year, 1/4 of the year so 12/4 = 3

2451 months is 204 years and 3 months

3 months after October is January

10 + 3 = 13 where December is 12 and the 13th month is January

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Point slope form equation:
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3 years ago
Which expression is equivalent to 4x2 + 9x – (x – 3)2 + 11?
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2.94 + 45 + 58.06<br> Help
stealth61 [152]

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106

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F(t) = -(t-2) (t-15)
Goryan [66]

Answer:

smaller (t) = 2 and this in coordinates form (2,0)

larger (t) = 15 and this in coordinates form (15,0)

the vertex of the parabola =  (\frac{17}{2} ,\frac{169}{4} ) or in decimals (8.5, 42.25)

Step-by-step explanation:

  • For the zeros of the function take each bracket and make it equal to zero.

SMALLER (t):

(t-2)=0

(add 2 for both sides)

t=2

LARGER (t):

(t-15)=0

(add 15 for both sides)

t=15

  • For the vertex of the parabola you do:

step1: expand the brackets:

f(t)=-(t-2)(t-15)

f(t)= -t^{2} +17t-30

step2: define a,b and c using the expression ax^{2} +bx+c :

a= -1 (the coefficient of t^{2} )

b= 17 (the coefficient of t)

c= -30 (the single number without a letter)

step3: sub the values in the formula -\frac{b}{2a} to find the x coordinate of the vertex :

-\frac{b}{2a}

= - \frac{17}{2*-1}

= \frac{17}{2} or in decimals 8.5

step4: sub the value of t (the x-coordinate) in equation f(t):

f(t)= -t^{2} +17t-30

f ( \frac{17}{2})  = - (\frac{17}{2} )^{2}+ 17× \frac{17}{2} - 30

= -\frac{289}{4} + \frac{289}{2} -30

=\frac{169}{4} or in decimals 42.25

(THIS IS A PICTURE OF THE GRAPH↓)

6 0
3 years ago
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