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2 years ago

This month is October. Which month will 2451 months be later?

Mathematics

1 answer:

amid [387]2 years ago

8 0

Answer:

January

Step-by-step explanation:

The month October is the 10th month,

there is 12 months in a year

2451 / 12 = 204.25

0.25 of a year, 1/4 of the year so 12/4 = 3

2451 months is 204 years and 3 months

3 months after October is January

10 + 3 = 13 where December is 12 and the 13th month is January

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Which of these points are on a line that has a slope of -3?

Ira Lisetskai [31]

Simple....

using the formula $\frac{ y_{1}- y_{2} }{ x_{1}- x_{2} }$ to find slope....

1.) (9,2)(4,3)

$\frac{2-3}{9-4}= -\frac{1}{5}$ (No)

2.) (9,2)(3,4)

$\frac{2-4}{9-3} = -\frac{2}{6} =- \frac{1}{3}$ (No)

3.) (2,9)(3,4)

$\frac{9-4}{2-3} = \frac{5}{-1} =-5$ (No)

4.) (2,9)(4,3)

$\frac{9-3}{2-4} = \frac{6}{-2} =-3$ (YES!)

Thus, your answer.

3 0

3 years ago

PLS SOMEONE HELP PLSSS

Sav [38]

Answer:

x=17

Step-by-step explanation:

ok so since lines PR and RQ are congruent (we know because of the lines on them), that means angles P and Q are also equal.

now we can set up the equation to find x like this:

29+29+(8x-14)=180 (180 because the three angles of a triangle always equal 180)

x=17

8 0

3 years ago

Which equation is true for x = 1.8?

Rina8888 [55]

Answer:

First equation is the right answer.

X÷3=0.6

1.8÷3=0.6

0.6=0.6

Hence proved

7 0

3 years ago

Read 2 more answers

Just number 14 pls <br> Zoom in if needed

o-na [289]

A, dilation because the shape got larger. The other three options just move it around

8 0

3 years ago

6x – 3y = 8

Nat2105 [25]

Answer:

Step-by-step explanation:

<em>The linear equation where:</em>

$\large \boldsymbol {} \sf y=\underbrace{m}_{slope }x \ +\underbrace{b} _{y -intersept}$

Solution :

$\displaystyle \sf \#13. \\\\ 6x-3y=8 \\\\\ -3y=8-6x \\\\y=-\frac{8-6x}{3} \\\\ \boxed{\sf y=2x-2\frac{1}{3} }} \\\\ slope =2 \\\\ y-intersept =-2\frac{1}{3} \\\\-------------$

$\sf \#14 . \\\\\\ 7x=5y+2 \\\\5y=7x-2 \\\\y =\dfrac{7x-2}{5} \\\\ \boxed{\sf y=1,4x-0,4} \\\\slope = 1,4 \\\\y-intersept =-0,4 \\\\---------------$

$\dispalystye \sf \#15. \\\\ -6y+4x=8 \ |\div2 \\\\-3y+2x=4 \\\\ y=-\dfrac{4-2x}{3} \\\\ y=\boxed{\sf \frac{2x-4}{3} } \\\\slope = \dfrac{2}{3} \\\\ y-intersept = -\dfrac{4}{3 }\\\\ -----------------$

$\sf \#16 .\\\\ x+y=2x+3 \\\\y=2x-x+3 \\\\\boxed{\sf y=1\cdot x+3} \\\\slope =1 \\\\y-intersept =3$

4 0

2 years ago