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Luden [163]
2 years ago
13

14 What are the solutions to the equation 3(x − 4)² = 27?

Mathematics
1 answer:
Marat540 [252]2 years ago
4 0

Answer:

(1) 1 and 7

Step-by-step explanation:

Hello!

We can solve by isolating the variable.

<h3>Solve</h3>
  • 3(x - 4)² = 27
  • (x - 4)² = 9
  • √(x - 4)² = √9
  • (x - 4) = ± 3
  • x = 4 ± 3

There are two solutions, 1 and 7.

The answer is option 1: x = 7, x = 1.

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What is the slope of the line?
Vesnalui [34]
It's a flat horizontal line so the slope is 0

Slope = rise/run = 0/run = 0

The "run" can be any number you want as long as it's not 0. 
4 0
3 years ago
Read 2 more answers
1948 Olympics
mash [69]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

Read more on Brainly.com - brainly.com/question/14915771#readmore

8 0
3 years ago
Help me find the scale factor​
atroni [7]
The scale factor for the first one is 2.25
And for the second one it’s 7
I hope this helps :)
3 0
3 years ago
-3+ 3x (x-7)=-6 (-5+ 4×)
Dennis_Churaev [7]
The answer to this question using the quadratic formula is x= -1+3√5/2 and x=-1-3<span>√5/2
</span>that is a square root, or, 3 times the square root of 5 ALL over 2, except for the 1. Same with the other one.
8 0
3 years ago
The coordinates of the point that is a reflection of Y(-4, -2) across the x-axis are ( , ). The coordinates of the point that is
AURORKA [14]

Answer:

Reflection across the x-axis: (-4,2)

Reflection across the y-axis: (4,-2)

Step-by-step explanation:

Going based off of what I see, a reflection across the x axis changes "y" & the same rule applies to the y axis.

It should be an L shape.

7 0
3 years ago
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