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RoseWind [281]
3 years ago
7

The line segment is extended to cross both axes. What is the location of the y-intercept on the line?

Mathematics
2 answers:
Kobotan [32]3 years ago
8 0

Answer: B. (0,-10)

(I got it right in the exam review.)

Flauer [41]3 years ago
8 0

Answer:

The answer is B.

Step-by-step explanation:

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Please help i will mark branliest!!
viktelen [127]

Answer:

the answer is B:14 inches

Step-by-step explanation:

because 52x14=728

7 0
3 years ago
(3^6)^-2/(6^-9*-2^10)
kaheart [24]
\frac{(3^{6})^{-2}}{(6^{-9}*-2^{10})}\\
\frac{3^{-12}}{(6^{-9}*-2^{10})}\\
\frac{6^{9}}{(3^{12}*-2^{10})}\\
\frac{10077696}{531441*-1024}=-0.0185185
6 0
3 years ago
If y=2x-3 find the value of y when x=2
Evgesh-ka [11]
Y = 2x - 3
Y = 2(2) - 3
Y = 4 - 3
Y = 1.

The y value or y coordinate is 1.
8 0
3 years ago
Read 2 more answers
write the equation and find the value of x. round side length to the nearest tenth and angle measures to the nearest degree​
mash [69]

Answer:

  • x = 12.5

Step-by-step explanation:

<u>Equation:</u>

  • cos 28 = 11/x
  • x = 11/ cos 28
  • x = 12.5 (rounded)
3 0
3 years ago
Asa received scores of 72, 97, and 82 on her last three math tests. she needs a mean test score of 82 to qualify for the math te
lara [203]

First step is to find what should be the required total of sum of Score after fourth test, to identify how much more or less she need to score in his fourth test.

Since Mean = (Sum of Scores)/number of test

using above formula we determine what is the required sum of score.

82 = (Sum of Scores)/4

⇒ 82 × 4 = 328

So in four test she should have score total as 328

So Score require in fourth test = Required Score Total - (total score in 3 tests)

             = 328 - ( 72 + 97 + 82 ) = 77

So she need score of 77 to be at mean of 82 after fourth test and get qualify for the team


6 0
4 years ago
Read 2 more answers
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