In a parallelogram, the opposite angles will be congruent to each other.
In this parallelogram, angles B and C are congruent, and angles A and D are congruent.
We will work on angles B and C first. Set the two angles to equal each other:

Subtract 6 from both sides:

Subtract 6x from both sides:

Divide both sides by 6 to get x by itself:

x will equal 10.
Set angles A and D to equal each other:

Divide both sides by 3 to get y by itself:

y will equal 18.
The x and y values that make this quadrilateral a parallelogram will be x = 10, and y = 18.
Answer:
294
Step-by-step explanation:
Difference means subtraction, so you just subtract 533 from 827.
827-533=294
hope this helps! : )
Answer:
60% I hope I help :) have a great day
NOTES:
- squared (²) means multiply that number by itself 2 times
- cubed (³) means multiply that number by itself 3 times
- square root (√) means 2 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
- cubed root (∛) means 3 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
Answer: (C) 41
<u>Step-by-step explanation:</u>
![\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41](https://tex.z-dn.net/?f=%5Cquad%206%5E2%2B%5Csqrt%5B3%5D%7B125%7D%20%5C%5C%3D%206%20%5Ccdot%206%2B%5Csqrt%5B3%5D%7B5%5Ccdot%205%20%5Ccdot%205%7D%5C%5C%3D%2036%20%2B%205%5C%5C%3D%2041)
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Answer: (C) 10
<u>Step-by-step explanation:</u>
![\bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}](https://tex.z-dn.net/?f=%5Cbigg%28%5Cdfrac%7B7%7D%7B3%7D%5Ctimes%20%5Csqrt%5B3%5D%7B27%7D-2%5Cbigg%29%5Ctimes%20%5Cdfrac%7B1%7D%7B5%7D%20%2B%20%5Csqrt%7B81%7D)
![=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}](https://tex.z-dn.net/?f=%3D%5Cbigg%28%5Cdfrac%7B7%7D%7B3%7D%5Ctimes%20%5Csqrt%5B3%5D%7B3%5Ccdot%203%20%5Ccdot%203%7D-2%5Cbigg%29%5Ctimes%20%5Cdfrac%7B1%7D%7B5%7D%20%2B%20%5Csqrt%7B9%5Ccdot%209%7D)





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8² = 8 · 8 = 64 11² = 11 · 11 = 121
5³ = 5 · 5 · 5 = 125 3³ = 3 · 3 · 3 = 27
![\sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%3D%5Csqrt%5B3%5D%7B4%5Ccdot%204%5Ccdot%204%7D%3D4)
![\sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8000%7D%3D%5Csqrt%5B3%5D%7B20%5Ccdot%2020%5Ccdot%2020%7D%3D20)