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2 years ago

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What is the slope-intercept form equation of the line that passes through (1, 3) and (3, 7)? (1 point) y = −2x + 1 y = −2x − 1 y

= 2x + 1 y = 2x − 1

1 answer:

Stolb23 [73]2 years ago

3 0

Answer: y=2x+1

Step-by-step explanation:

The slope of the line is $\frac{7-3}{3-1}=\frac{4}{2}=2$

Using the point (1,3) to substitute into point-slope form,

$y-3=2(x-1)\\\\y-3=2x-2\\\\\boxed{y-2x+1}$

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A new shopping mall is considering setting up an information desk manned by one employee. Based upon information obtained from s

quester [9]

Answer:

a) $P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

b) $p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

c) $L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

d) $L_q =\frac{20^2}{30(30-20)}=1.333 people$

e) $W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

f) $W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

Step-by-step explanation:

Notation

P represent the probability that the employee is idle

$p_x$ represent the probability that the employee is busy

$L_s$ represent the average number of people receiving and waiting to receive some information

$L_q$ represent the average number of people waiting in line to get some information

$W_s$ represent the average time a person seeking information spends in the system

$W_q$ represent the expected time a person spends just waiting in line to have a question answered

This an special case of Single channel model

Single Channel Queuing Model. "That division of service channels happen in regards to number of servers that are present at each of the queues that are formed. Poisson distribution determines the number of arrivals on a per unit time basis, where mean arrival rate is denoted by λ".

Part a

Find the probability that the employee is idle

The probability on this case is given by:

In order to find the mean we can do this:

$\mu = \frac{1question}{2minutes}\frac{60minutes}{1hr}=\frac{30 question}{hr}$

And in order to find the probability we can do this:

$P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

Part b

Find the proportion of the time that the employee is busy

This proportion is given by:

$p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

Part c

Find the average number of people receiving and waiting to receive some information

In order to find this average we can use this formula:

$L_s= \frac{\lambda}{\lambda -\mu}$

And replacing we got:

$L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

Part d

Find the average number of people waiting in line to get some information.

For the number of people wiating we can us ethe following formula"

$L_q =\frac{\lambda^2}{\mu(\mu-\lambda)}$

And replacing we got this:

$L_q =\frac{20^2}{30(30-20)}=1.333 people$

Part e

Find the average time a person seeking information spends in the system

For this average we can use the following formula:

$W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

Part f

Find the expected time a person spends just waiting in line to have a question answered (time in the queue).

For this case the waiting time to answer a question we can use this formula:

$W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

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Identify the independent and dependent variables. Write a function in function notation. Then use the function to solve the prob

bekas [8.4K]

Answer:

He is being paid $180 on Monday.

Step-by-step explanation:

Since it asks for function notation, I'll relate the variables accordingly. So, x, the independent variable, is the one that is being adjusted. That would be the amount of miles that he is assigned so x = miles assigned. Next, the dependent variable, f(x), is the amount of cash he is paid, so f(x) = total amount paid.

Here is the function that can be used to represent the situation:

f(x) = 3.50x + 75

Now, plug in 30 to find out how much he earns after completing a 30 mile route:

f(30) = 3.50(30) + 75

f(30) = 105 + 75

f(30) = 180

Also, the $75 is a fixed amount. No variable association.

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