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Xelga [282]
2 years ago
8

What is the slope-intercept form equation of the line that passes through (1, 3) and (3, 7)? (1 point) y = −2x + 1 y = −2x − 1 y

= 2x + 1 y = 2x − 1
Mathematics
1 answer:
Stolb23 [73]2 years ago
3 0

Answer: y=2x+1

Step-by-step explanation:

The slope of the line is \frac{7-3}{3-1}=\frac{4}{2}=2

Using the point (1,3) to substitute into point-slope form,

y-3=2(x-1)\\\\y-3=2x-2\\\\\boxed{y-2x+1}

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Solve step by step solution then only i can do it plxx ​
Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So \triangle ABC and \triangle ABD Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

  • BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

\longrightarrow\sf h=17cm

\therefore{\underline{\boxed{\bf x=17cm}}}

3 0
3 years ago
2X+15= -3x how do you work this equation​
Sphinxa [80]

Answer: x=-3

<u>Add 3x to both sides</u>

<u></u>2x+15+3x=-3x+3x\\5x+15=0<u></u>

<u></u>

<u>Subtract 15 from both sides</u>

<u></u>5x+15-15=0-15\\5x=-15<u></u>

<u></u>

<u>Divide both sides by 5</u>

<u></u>5x/5=-15/5\\x=-3<u></u>

8 0
3 years ago
Read 2 more answers
What is the area of the following circle?
Marysya12 [62]

Answer:

Area = pi X r^2 = pi x (1)^2 = 3.14 x 1 = 3.14

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A college student is taking two courses. The probability she passes the first course is 0.73. The probability she passes the sec
zhenek [66]

Answer:

b) No, it's not independent.

c) 0.02

d) 0.59

e) 0.57

f) 0.5616

Step-by-step explanation:

To answer this problem, a Venn diagram should be useful. The diagram with the information of Event 1 and Event 2 is shown below (I already added the information for the intersection but we're going to see how to get that information in the b) part of the problem)

Let's call A the event that she passes the first course, then P(A)=.73

Let's call B the event that she passes the second course, then P(B)=.66

Then P(A∪B) is the probability that she passes the first or the second course (at least one of them) is the given probability. P(A∪B)=.98

b) Is the event she passes one course independent of the event that she passes the other course?

Two events are independent when P(A∩B) = P(A) * P(B)

So far, we don't know P(A∩B), but we do know that for all events, the next formula is true:

P(A∪B) = P(A) + P(B) - P(A∩B)

We are going to solve for P (A∩B)

.98 = .73 + .66 - P(A∩B)

P(A∩B) =.73 + .66 - .98

P(A∩B) = .41

Now we will see if the formula for independent events is true

P(A∩B) = P(A) x P(B)

.41 = .73 x .66

.41 ≠.4818

Therefore, these two events are not independent.

c) The probability she does not pass either course, is 1 - the probability that she passes either one of the courses (P(A∪B) = .98)

1 - P(A∪B) = 1 - .98 = .02

d) The probability she doesn't pass both courses is 1 - the probability that she passes both of the courses P(A∩B)

1 - P(A∩B) = 1 -.41 = .59

e) The probability she passes exactly one course would be the probability that she passes either course minus the probability that she passes both courses.

P(A∪B) - P(A∩B) = .98 - .41 = .57

f) Given that she passes the first course, the probability she passes the second would be a conditional probability P(B|A)

P(B|A) = P(A∩B) / P(A)

P(B|A) = .41 / .73 = .5616

4 0
3 years ago
PLS HELP ASAP!! ALGEBRA 9!!<br> 4.29-x+36=102-2.52x+2
Andrei [34K]

Answer:

  x = 29

Step-by-step explanation:

If the equation is :

4.2(9-x)+36=102-2.5(2x+2)

→distribute 4.2 and -2.5 in parenthesis

4.2(9 - x) + 36 = 102 -2.5(2x + 2)

37.8 - 4.2x +36 = 102 -5x -5

→  have terms with x = terms without x

Keep the terms you need the way they are, and move the terms you need on the other side of equal sign with changed sign.

4.2(9 - x) + 36 = 102 -2.5(2x + 2)

37.8 - 4.2x +36 = 102 -5x -5

 - 4.2x  +5 x  = - 37.8 - 36 + 102 - 5

→ Combine like terms

             0.8x  = 23.2

→ Divide both sides by 0.8

                    x = 29

                   

4 0
2 years ago
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