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ch4aika [34]
2 years ago
6

Which of the following would increase the amount of electricity generated by a wind turbine

Physics
1 answer:
kotykmax [81]2 years ago
8 0

Higher wind speeds would increase the amount of electricity generated by a wind turbine.

<h3>What is a power plant?</h3>

A power plant is an industrial structure that generates electricity. The majority of power plants are linked to the electrical grid.

Stronger winds produce greater power because they enable the blades to revolve more quickly. Greater mechanical and electrical power from the generator result from faster spinning.

Hence, higher wind speeds would increase the amount of electricity generated by a wind turbine.

To learn more about the power plant, refer to the link;

brainly.com/question/7670779

#SPJ1

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A sanding disk with rotational inertia 1.2 10-3 kg·m2 is attached to an electric drill whose motor delivers a torque of 10 N·m a
tensa zangetsu [6.8K]

Answer:

Angular momentum = 0.7 kg.m²/s

Angular velocity = 583.3 rad/s

Explanation:

1. The torque τ  is related to the angular momentum L by the relation

τ = ΔL/Δt

ΔL = τΔt

τ = 10 N. m

Δt = 70 ms = 70 × 10⁻³s

ΔL = (10 N. m) × (70 × 10⁻³s) = 700 × 10⁻³ kg.m²/s = 0.7 kg.m²/s

2. The rotational inertia I relates the angular momentum L to the angular velocity w

L = Iw

w = L/I

L =  0.7 kg.m²/s

I = 1.2 × 10⁻³ kg.m²

w = (0.7 kg.m²/s)/(1.2 × 10⁻³ kg.m²) = 583.3 rad/s

4 0
3 years ago
Help pleaseeeeeeeeeeeeee
77julia77 [94]

Answer:

hello the answer is 47m/s

8 0
3 years ago
How many planets are in our solar system? and how many moons are there in total?
Step2247 [10]

There are NINE planets in our solar system: Mars, Venus, Jupiter, Saturn, Uranus, Neptune, Earth, Mercury, Pluto.

As of this year, there are 350 moons in our solar system, 175 of which orbit about our planets.

I hope this helps!

5 0
4 years ago
Read 2 more answers
The SI unit for force is the newton. Which of the following is equivalent to a newton? A. kg/m B. kg·m/s2 C. kg·m/s D. kg·m/s
bearhunter [10]
I may be wrong but A
8 0
3 years ago
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Gauss's law combines the electric field over a surface with the area of the surface. From Coulomb's law we know that the electri
Romashka-Z-Leto [24]

The change in surface area of Gaussian surface with radius (r) is 8πr.

<h3>Electric field from Coulomb's law</h3>

The electric field experienced by a charge is calculated as follows;

E = \frac{Q}{4\pi \varepsilon_o r^2}

where;

  • E is the electric field
  • Q is the charge
  • r is the radius

The electric field reduces by a factor of \frac{1}{r^2}

<h3>Surface area of a Gaussian surface;</h3>

The surface area of a sphere is given as;

A = 4\pi r^2

<h3>Change in area with r</h3>

\frac{dA}{dr} = 8\pi r

Thus, the change in surface area of Gaussian surface with radius (r) is 8πr.

Learn more about area of Gaussian surfaces here: brainly.com/question/17060446

7 0
2 years ago
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