1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
34kurt
3 years ago
15

The built-up beam is formed by welding together the thin plates of thickness 5 mm. determine the location of the shear center o.

Physics
1 answer:
atroni [7]3 years ago
4 0

Answer:

The location of the shear center o is 0.033 or 33 m

Explanation:

Solution

Recall that,

The moment of inertia of the section is =  I = 0.05 * 0.4 ^3 /12 + 0.005 * 0.2 ^3/12

= 30 * 10 ^ ⁻⁶ m⁴

Now,

The first moment of inertia is

Q =ῩA = [ (0.1 -x) + x/2] (0.005 * x)

= 0.5x * 10 ^⁻³ - 2.5 x * 10⁻³ x²

Thus,

The shear flow is,

q =  VQ/I

so,

P =  (0.5x * 10 ^⁻³ - 2.5 x * 10⁻³ x²)/ 30 * 10 ^⁻⁶

P = (16.67 x - 83. 33  x²)

The shear force resisted by the shorter web becomes

Vw,₂ = 2∫ = ₀.₁ and ₀ = P (16.67 x - 83. 33  x²) dx = 0.11x

Then,

We take the moment at a point A

∑Mₐ = 0

- ( p * e)- (Vw₂ * 0.3 ) = 0

e =  0.11 p * 0.3/p

which gives us 0.033 m

= 33 m

Therefore the location of the shear center o is 0.033 or 33 m

Note: Kindly find an attached diagram to the question given above as part of the explanation solved with it.

You might be interested in
You push a 85 kg shopping cart from rest with a net force of 250 n for 5 seconds,at which point it flies off a cliff that is 100
Vikki [24]

m = mass of the cart = 85 kg

F = net force on the cart = 250 N

a = acceleration of the cart

acceleration of the cart is given as

a = F/m

a = 250/85

a = 2.94 m/s²

t = time for which the force is applied = 5 sec

v₀ = initial velocity of the cart = 0 m/s

v = final velocity of the cart just before  it flies off the cliff = ?

using the equation

v = v₀ + a t

inserting the values

v = 0 + (2.94) (5)

v = 14.7 m/s

consider the motion of cart after it flies off the cliff in vertical direction :

v' = initial velocity in vertical direction = 0 m/s

a' = acceleration in vertical direction = g = acceleration due to gravity = 9.8 m/s²

t' = time taken for the cart to land = ?

Y' = vertical displacement of the cart = height of cliff = 100 m

using the kinematics equation

Y' = v' t' + (0.5) a' t'²

100 = (0) t' + (0.5) (9.8) t'²

t' = 4.52 sec


consider the motion of cart along the horizontal direction after it flies off the cliff

X = distance traveled from the base of cliff = ?

t' = time of travel = 4.52 sec

v = velocity along the horizontal direction = 14.7 m/s

distance traveled from the base of cliff is given as

X = v t'

X = 14.7 x 4.52

X  = 66.4 m


3 0
3 years ago
A toy car has a momentum of 3 kilogram meters per second south. The car has a 1-kilogram mass. Which is the velocity of the car?
antiseptic1488 [7]
Using p = mv 3 = 1× v v = 3m/s
6 0
3 years ago
Need help in the middle one
kondor19780726 [428]

Answer:

Guysi hate math answer this guy plsss ssss

7 0
3 years ago
Four identical particles of mass 0.980 kg each are placed at the vertices of a 4.14 m x 4.14 m square and held there by four mas
Zielflug [23.3K]

Answer:

a) The rotational inertia when it passes through the midpoints of opposite sides and lies in the plane of the square is 16.8 kg m²

b) I = 50.39 kg m²

c) I = 16.8 kg m²

Explanation:

a) Given data:

m = 0.98 kg

a = 4.14 * 4.14

The moment of inertia is:

I=mr^{2} \\r=\frac{a}{2} \\I=m(a/2)^{2} \\I=\frac{ma^{2} }{4}

For 4 particles:

I=4(\frac{ma^{2} }{4} )=ma^{2} =0.98*(4.14)^{2} =16.8kgm^{2}

b) Distance from top left mass = x = a/2

Distance from bottom left mass = x = a/2

Distance from top right mass = x = √5 (a/2)

The total moment of inertia is:

I=m(\frac{a}{2} )^{2} +m(\frac{a}{2} )^{2}+m(\frac{\sqrt{5a} }{2} )^{2}+m(\frac{\sqrt{5a} }{2} )^{2}=\frac{12ma^{2} }{4} =3ma^{2} =3*0.98*(4.14)^{2} =50.39kgm^{2}

c)

I=2m(\frac{m}{\sqrt{2} } )^{2} =ma^{2} =0.98*(4.14)^{2} =16.8kgm^{2}

8 0
3 years ago
A student notices that an inflated balloon gets larger when it is warmed by a lamp. Which best describes the mass of the balloon
nirvana33 [79]
It gets larger because
well let me give you an example
so today in class we looked at a lava lamp with wax inside and there was a lightbulb at the bottom.
we watched as the wax floated up because the molecules inside the wax spreads out and makes the wax less dense.
the wax floats up because (which is related to the balloon getting bigger) the wax is getting less dense and the particles get bigger which ALSO makes the wax less dense.
hope this helps and hope you can relate it to your problem! say thanks if I did help AT ALL! :)
7 0
3 years ago
Read 2 more answers
Other questions:
  • What observations characterize solar maximum?
    10·1 answer
  • Kinetic Energy RE-
    11·1 answer
  • The floor leader of the major party that holds fewer seats in a house of congress is called _____. 1.the speaker of the house 2.
    9·2 answers
  • Which statement about atmospheric pressure near earth's surface is true
    6·1 answer
  • Whats the origin of all stars?<br> a) supernova<br> b) dwarfs<br> c) protostars<br> d) nebulae
    7·2 answers
  • A charged ball is moving horizontally and perpendicular to a magnetic field of 0.8 Tesla. The ball has a mass of 0.007 kg and ha
    6·2 answers
  • "require people to consider what is right and wrong"
    15·1 answer
  • When you voice the vowel sound in "hat," you narrow the opening where your throat opens into the cavity of your mouth so that yo
    11·1 answer
  • An object originally at rest, is accelerated uniformly along a straight line to a speed of 8m/s in 2s. What is the acceleration
    10·1 answer
  • Find the x-component of this
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!