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3 years ago

Hi :) how to do this?

Physics

1 answer:

fredd [130]3 years ago

4 0

Answer:

The answer is b

Hope this helps you!

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if a stone with an original volcity of 0 is falling from the ledge and takes 8 seconds to hit the ground what is the final volci

Nookie1986 [14]

On Earth, gravity adds 9.8 m/s to the downwsrd speed of any falling object, every second. Beginning from zero downward speed, the speed grows to (8 x 9.8) = 78.4 m/s downward after 8 sec.

7 0

3 years ago

A potentialiterence of 12 volts is induced across a straight wire 0.20 meters long as it is moved at a constant speed of 3.0 met

shtirl [24]

Strength of the magnetic field: 20 T

Explanation:

For a conductive wire moving perpendicular to a magnetic field, the electromotive force (voltage) induced in the wire due to electromagnetic induction is given by

$\epsilon=BvL$

where

B is the strength of the magnetic field

v is the speed of the wire

L is the length of the wire

For the wire in this problem, we have:

$\epsilon=12 V$ (induced emf)

L = 0.20 m (length of the wire)

v = 3.0 m/s (speed)

Solving for B, we find the strength of the magnetic field:

$B=\frac{\epsilon}{vL}=\frac{12}{(0.20)(3.0)}=20 T$

Learn more about magnetic fields:

brainly.com/question/3874443

brainly.com/question/4240735

#LearnwithBrainly

6 0

3 years ago

The energy that's given to the body by food is A. measured in units called calories. B. best obtained by eating high protein. C.

mel-nik [20]

Answer:

Calories, however you might want to back up my answer. I havent studied this topic in a while.

4 0

3 years ago

5. Which of the folowing statements about the energy ofa pendulum is true?

Mars2501 [29]

Answer:

Explanation:

total energy = potential energy + kinetic energy

8 0

3 years ago

How to solve 2.14 using calculus

trasher [3.6K]

Answer:

The acceleration is $6.42\frac{m}{s^2}$

Explanation:

Given the velocity function:

$v=0.86\frac{m}{s^3}t^2$

you can obtain the instantaneous acceleration "a" as its first derivative:

$a=\dot{v}=2\cdot0.86\frac{m}{s^3}\cdot t=1.72\frac{m}{s^3}t$

To determine the value of "a" when the velocity was 12m/s, you need to figure out the value for "t" when this happens. At what time t is the velocity 12m/s?

$12.0\frac{m}{s}=0.86\frac{m}{s^3}t^2\implies t=3.74s$

This value of t is less than the 5 seconds mentioned in the text - so that is a good sign that the formula is valid for this value. And so you can use t=3.47s in the derivative (acceleration) above:

$a=1.72t=1.72\frac{m}{s^3}\cdot 3.74s = 6.42\frac{m}{s^2}$

3 0

3 years ago