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Dafna11 [192]
4 years ago
9

Can you guys help me ?

Mathematics
2 answers:
AysviL [449]4 years ago
8 0

Answer:

C the 12th root of (8^x)

Step-by-step explanation:

This becomes 8 ^ x/4  ^ 1/3

We know that a^b^c = a^ (c*c)

8 ^(x/12)

Lady_Fox [76]4 years ago
6 0

Your answer would be \sqrt[12]{8}^{2}.

Approaching this problem would be easier by converting the cube root of 8 to 8 to the power of 1/3. Remember that when you take anything to the nth root, it is the same as taking something to the power of 1 / n.

Therefore, the equation becomes (x^{1/3} )^{\frac{1}{4}x }.

Now, to keep simplifying, recall that when you do n^{x^y}, it can become n^{x*y}.

This can be applied in this situation. You are taking 8 to the power of 1/3 to the power of 1/4x. Now, you can multiply the two "to the power of's" to get 8^{\frac{1}{12}x }. Applying the same logic, it becomes 8^{\frac{1}{12} *x}  = 8^{\frac{1}{12} ^x}.

Now, all you have to do is use the same logic as used in the very beginning. Raising something to the power of 1/12 can become taking it to the 12th root. So therefore, the equation would be \sqrt[12]{8}^{x}

Good luck!

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<u>Pre-Algebra</u>

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<u>Step 1: Define systems</u>

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<u>Step 2: Rewrite systems</u>

  1. Define:                                        3x - 2y = 27
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  4. Subtract 10/3y on both sides:      -7/3y = 42
  5. Divide -7/3 on both sides:            y = -18
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