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Dafna11 [192]
3 years ago
9

Can you guys help me ?

Mathematics
2 answers:
AysviL [449]3 years ago
8 0

Answer:

C the 12th root of (8^x)

Step-by-step explanation:

This becomes 8 ^ x/4  ^ 1/3

We know that a^b^c = a^ (c*c)

8 ^(x/12)

Lady_Fox [76]3 years ago
6 0

Your answer would be \sqrt[12]{8}^{2}.

Approaching this problem would be easier by converting the cube root of 8 to 8 to the power of 1/3. Remember that when you take anything to the nth root, it is the same as taking something to the power of 1 / n.

Therefore, the equation becomes (x^{1/3} )^{\frac{1}{4}x }.

Now, to keep simplifying, recall that when you do n^{x^y}, it can become n^{x*y}.

This can be applied in this situation. You are taking 8 to the power of 1/3 to the power of 1/4x. Now, you can multiply the two "to the power of's" to get 8^{\frac{1}{12}x }. Applying the same logic, it becomes 8^{\frac{1}{12} *x}  = 8^{\frac{1}{12} ^x}.

Now, all you have to do is use the same logic as used in the very beginning. Raising something to the power of 1/12 can become taking it to the 12th root. So therefore, the equation would be \sqrt[12]{8}^{x}

Good luck!

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Answer:

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storchak [24]

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a four-sided figure.

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Two different right cones are being considered by a design team to hold one liter (1000
ollegr [7]

Answer:

The surface area of Design A is smaller than the surface area of Design B.

The area of Design A is 94.65% of the Design B.

Step-by-step explanation:

The area of a right cone is given by the sum of the circle area of the base and the lateral area:

A = \pi r^{2} + \pi rL   (1)

Where:

r: is the radius

L: is the slant height  

The slant height is related to the height and to the radius by Pitagoras:

L^{2} = H^{2} + r^{2}  

L = \sqrt{H^{2} + r^{2}}    (2)

By entering equation (2) into (1) we have:

A = \pi r^{2} + \pi r(\sqrt{H^{2} + r^{2}})  

Now, let's find the area of the two cases.

Design A: height that is double the diameter of the base, H= 2D = 4r

A_{1} = \pi r^{2} + \pi r(\sqrt{(4r)^{2} + r^{2}}) = \pi r^{2}(1+ \sqrt{17})  

The volume of the cone is:

V = \frac{1}{3}\pi r^{2}H

We can find "r":

V = \frac{1}{3}\pi r^{2}(4r) = \frac{4}{3}\pi r^{3}

r = \sqrt[3]{\frac{3V}{4\pi}} = \sqrt[3]{\frac{3*1000}{4\pi}} = 6.20 cm

The area is:

A_{1} = \pi (6.20)^{2}(1+ \sqrt{17}) = 618.7 cm^{2}  

Design B: height that is triple the diameter of the base, H = 3D = 6r                  

The radius is:

r = \sqrt[3]{\frac{3V}{6\pi}} = \sqrt[3]{\frac{3*1000}{6\pi}} = 5.42 cm  

The area is:

A_{2} = \pi r^{2} + \pi r(\sqrt{(6r)^{2} + r^{2}}) = \pi r^{2}(1 + \sqrt{37}) = \pi (5.42)^{2}(1 + \sqrt{37}) = 653.7 cm^{2}  

Hence, the surface area of Design A is smaller than the surface area of Design B.

The percent of the surface area of Design A is less than Design B by:

\% A = \frac{618.7 cm^{2}}{653.7 cm^{2}}\times 100 = 94.65 \%

Therefore, the area of Design A is 94.65% of the Design B.

                         

I hope it helps you!

3 0
3 years ago
A) what percent is the 10 cm length of 8cm length?
Hatshy [7]
125 percent you divide 10 by 8 and get 1.25 then moved the decimal point to the right two spots
5 0
3 years ago
What’s the pattern rule?
Verdich [7]

Answer:

Input-previous input then multiply this difference by 3, add the squared difference to the previous output to get the current output

Step-by-step explanation:

The first output is predetermined then the subsequent outputs are obtained by subtracting previous input from previous output then we multiply the difference by 3 and add to the previous output for example

{(7-4)\times 3}+32=9+32=41

{(10-7)\times 3}+41=9+41=50

{(12-10)\times 3}+50= 6+50=56

5 0
3 years ago
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