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2 years ago

Complete the slope-intercept form of the linear equation that represents the relationship in the table.

Mathematics

1 answer:

Mrac [35]2 years ago

6 0

The equation of the line that passes through points (-1, -10), and (3, 14) is y = 6x - 4.

<h3>What is a straight line?</h3>

A straight line is a combination of endless points joined on both sides of the point.

The slope 'm' of any straight line is given by:

$\rm m =\dfrac{y_2-y_1}{x_2-x_1}$

We have two points shown in the table:

(-1, -10), and (3, 14)

$\rm (y - 14 )= \dfrac{14+10}{3+1}(x-3)$

y - 14 = 6(x - 3)

y = 6x - 4

Thus, the equation of the line that passes through points (-1, -10), and (3, 14) is y = 6x - 4.

Learn more about the slope of the straight line here:

brainly.com/question/3493733

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Answer:

The value of AB is $\left[\begin{array}{ccc}21\\11\end{array}\right]$ and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

$A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right]$ , $B=\left[\begin{array}{ccc}3\\5\end{array}\right]$

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Matrix A has order 2 × 2 and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

$AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]$

$AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]$

$AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]$

$AB=\left[\begin{array}{ccc}21\\11\end{array}\right]$

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Now calculate the value of BA as shown:

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Matrix B has order 2 × 1 and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

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