What can be concluded about the sequence 19, 15, 11,
1 answer:
Option first and option second are correct because the common difference of the sequence is the same as the slope of the graph.
<h3>What is a sequence?</h3>
It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.
The question is incomplete.
The question is:
What can be concluded about the sequences 19, 15, 11, 7, . . . represented on the graph? Check all that apply.
- The common difference of the sequence is the same as the slope of the graph.
- The slope of the graph is –4.
- The next term in the sequence is represented by point (4, 3).
- f(x) = –4x + 19 represents the sequence.
- An infinite number of points can be determined to follow this sequence.
The graph is attached to the picture please refer to the graph.
We have an arithmetic sequence:
19, 15, 11, 7,...
The first term is:
a = 19
Common difference d = 15-19 = -4
The nth term:
a(n) = 19 + (n-1)(-4)
a(n) = 19 -4n + 4
a(n) = -4n + 23
We can write above expression as:
f(x) = -4x + 23
Slope of the equation = -4
The correct options are:
- The common difference of the sequence is the same as the slope of the graph.
- The slope of the graph is –4.
Thus, an option first and option second are correct because the common difference of the sequence is the same as the slope of the graph.
Learn more about the sequence here:
#SPJ1
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Answer:
Step-by-step explanation:
<em>Given:</em>
Mn is diameter of circle having centre O
and BD = OD,
<em><u>To prove that:</u></em>
<u></u>
<em>Solution:</em>
Join the points O and B and draw OB,
On joining the line,
in ∆OCD and ∆OBD,
OC =OB → (Radius of same circle)
BD =CD → (from given)
OD =OD → (Common side in both the triangles)
Hence ∆OCD and ∆OBD are congruent from SSS property.
so we can say that,
Consider above prove as statement A
Corresponding angles of congruent traingle.
in ∆ OAB,
OA = OB (radius of same circle)
hence ∆OAB is an isosceles traingle.
We know that opposite angle of isosceles traingle are always equal. hence,
Consider above prove as statement B
From Statement A & B we can say that
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