Answer:
d=5.39 units
Step-by-step explanation:
Given A (-3, -2)
T= (x+5, y-3)
T= (-3+5, -2-3)
T=(2,-5)
Applying the translation on;
A( -3,-2)
A' (-3+2, -2+ -5)
A'= (-1, -7)
Distance
d= 
A = (-3,-2) and A'(-1, -7)
d=√ (-1--3)² + (-7--2)²
d=√ (2)²+(-5)²
d=√4+25
d=√29
d=5.39 units
All you have to do is add 24 to both sides and you will get y. You add 24 so that it will cancel from one side but be added to the other.
The answer is y=17.
Hope this helps!


solve for "l" to find its length
Answer:
y = 4x + 14
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 4x + 7 ← is in slope- intercept form
with slope m = 4
• Parallel lines have equal slopes , then
y = 4x + c ← is the partial equation
to find c substitute (- 3, 2 ) into the partial equation
2 = - 12 + c ⇒ c = 2 + 12 = 14
y = 4x + 14 ← equation of parallel line