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AysviL [449]
2 years ago
11

Solve the quadratic equation using the quadratic formula: 3x^2 - 6x = 5

Mathematics
1 answer:
Fantom [35]2 years ago
8 0

Answer:

x_{1} = 1+\frac{2\sqrt{6}}{3} \\\\x_{2} = 1-\frac{2\sqrt{6}}{3}

Step-by-step explanation:

3x^2 - 6x - 5=0

quadratic formula:

x=\frac{-b+-\sqrt{b^{2}-4*a*c}}{2*a}

a=3     b=-6     c=-5

x=\frac{-(-6)+-\sqrt{(-6)^{2}-4*3*-5}}{2*3}

x=\frac{6+-\sqrt{36+60}}{6} \\\\x=\frac{6+-\sqrt{96}}{6} \\\\x=\frac{6+-\sqrt{2^{2}*2^{2}*2*3 }}{6} \\\\x=\frac{6+-4\sqrt{6}}{6} \\

so we have:

x_{1} = 1+\frac{2\sqrt{6}}{3} \\\\x_{2} = 1-\frac{2\sqrt{6}}{3}

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