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AysviL [449]
2 years ago
11

Solve the quadratic equation using the quadratic formula: 3x^2 - 6x = 5

Mathematics
1 answer:
Fantom [35]2 years ago
8 0

Answer:

x_{1} = 1+\frac{2\sqrt{6}}{3} \\\\x_{2} = 1-\frac{2\sqrt{6}}{3}

Step-by-step explanation:

3x^2 - 6x - 5=0

quadratic formula:

x=\frac{-b+-\sqrt{b^{2}-4*a*c}}{2*a}

a=3     b=-6     c=-5

x=\frac{-(-6)+-\sqrt{(-6)^{2}-4*3*-5}}{2*3}

x=\frac{6+-\sqrt{36+60}}{6} \\\\x=\frac{6+-\sqrt{96}}{6} \\\\x=\frac{6+-\sqrt{2^{2}*2^{2}*2*3 }}{6} \\\\x=\frac{6+-4\sqrt{6}}{6} \\

so we have:

x_{1} = 1+\frac{2\sqrt{6}}{3} \\\\x_{2} = 1-\frac{2\sqrt{6}}{3}

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If (ax^2 + 3x + 2b) - (5x^2+bx-3c)=3x^2-9, what is the value of A + B + C?
Rina8888 [55]

Answer:

We have the equation:

(ax^2 + 3x + 2b) - (5x^2+bx-3c)=  3x^2 - 9

First, move all to the left side.

(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0

Now let's group togheter terms with the same power of x.

(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.

This must be zero for all the values of x, then the things inside each parenthesis must be zero.

1)

a - 5 - 3 = 0

a = 3 + 5 = 8.

2)

3 - b = 0

b = 3.

3)

2b + 3c + 9 = 0

2*3 + 3c + 9 = 0

3c = -6 - 9 = -15

c = -15/3 = -5

Then we have:

a = 8, b = 3, c = -5

a + b + c = 8 + 3 - 5 = 6

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3 years ago
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Answer:

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Step-by-step explanation:

4 0
3 years ago
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Okay. So, what we do first is do the distributive property by multiply each number in the parenthesis by 3. When we do that, we get (6x + 12), because 3 * 2x is 6x and 4 * 3 is 12. Now, the numbers written out in long form is 5 + 6x + 12 + 6. 6x is in simplified form, because there is nothing that we can combine it with, but we do need to combine the whole numbers. 5 + 12 is 17, and 17 + 6 is 23. The expression in simplified form is 6x + 23. The answer is B.
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3 years ago
Find the result when 25 is increased by 52%
ANTONII [103]
38 is the answer because 25+13=38
8 0
2 years ago
Read 2 more answers
A government bureau publishes annual price figures for new mobile homes. A simple random sample of 36 new mobile homes yielded t
Oliga [24]

Answer:

The 99.7% confidence interval for the mean price of all new mobile homes is ($60,672, $65,622).

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>The prices in thousands of dollar are:</em>

<em>66.6, 69.8, 58.4, 57.3, 63.1, 61.8, 56, 72.7, 61.8,  </em>

<em>66.9, 72.6, 63.1, 58.7, 65.9, 61.1, 56.1, 49.9, 72.6,  </em>

<em>49, 56.4, 72.6, 60.1, 65, 64.8, 56.5, 52, 53.2,  </em>

<em>56.4, 75.4, 76.3, 60.5, 74.6, 57, 69.2, 62.7, 77.2.</em>

<em />

We have a sample of n=36 new mobile homes.

The mean of this sample is:

M=(1/36)\sum_{i=1}^{36}x_i=\dfrac{2273.3}{36}=63.147

The population standard deviation is σ=7.5 (in thousands of dollars).

The critical value of z for a 99.7% CI is z=2.97.

Then, we can calculate the margin of error as:

E=z\cdot \sigma/\sqrt{n}=2.97*7.5/\sqrt{36}=22.275/9=2.475

Now we can calculate the lower and upper bound of the confidence interval as:

LL=\bar X-E=63.147-2.475=60.672\\\\UL=\bar X+E=63.147+2.475=65.622

The 99.7% confidence interval for the mean price of all new mobile homes is ($60,672, $65,622).

8 0
3 years ago
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