Answer:
The initial speed of the car was 80 ft/s.
Step-by-step explanation:
The deceleration is the rate at which the car speed decreases. In this case the speed of the car goes all the way down to 0 ft/s and in order to do that it travelled 50 ft. So we will call the initial speed at which the car started to brake "v_0" and use Torricelli's equation to find it. The equation is given by:
v^2 = (v_0)^2 + 2*a*S
Where v is the final speed, v_0 is the initial speed, a is the rate of acceleration and S is the space travelled. Using the values that the problem gave to us we have:
0^2 = (v_0)^2 - 2*64*50
0 = (v_0)^2 - 6400
(v_0)^2 = 6400
v_0 = sqrt(6400) = 80 ft/s
Notice that in this case "a" was negative, since the car was decelerating instead of accelerating.
The initial speed of the car was 80 ft/s.
Answer:
3/8 = 9/24
Step-by-step explanation:
So here we have a basic multiplication problem and finding the LCM of 8 and 3. The first step in this problem is finding the LCM of 3/8. The LCM of 3 and 8 is 24. So yay! we have the bottom half of our answer!
Ex.-
The LCM of 8 and 3 is 24.
So now we have to find an equivalent fraction. Since we already know that 8 (the denominator in the original equation) can be multiplied by 3 to equal 24, we use 3 (the numerator in the original equation) and multiply it by itself to get an equivalent fraction.
Ex.-
8 x 3 = 24
3 x 3 = 9
Now that we have our numerator and denominator, all we have to do now is put them together to get our answer.
Ex.-
9/24 (answer) = 3/8 (original equation)
Hopefully I could help! :)
<span>
<u><em>Answer:</em></u>d = 25
<u><em>Explanation:</em></u>To get the value of d, we will need to isolate the d on one side of the equation.
<u>This can be done as follows:</u>
</span>
<span>
<u>First, we will do cross multiplication as follows:</u>
40*15 = 24*d
600 = 24d
<u>Then, we will isolate the d as follows:</u>
24d = 600
</span>
<span>
d = 25
Hope this helps :)</span>
Answer:
\left(x+3\right)\left(x-9\right)
Step-by-step explanation:
