Answer: w ≤ 14 cm , L ≤ 42 cm
<u>Step-by-step explanation:</u>
width (w): w
Length(L): 3w
Perimeter (P) = 2w + 2L
P ≤ 112
2w + 2L ≤ 112
2(w) + 2(3w) ≤ 112
2w + 6w ≤ 112
8w ≤ 112
w ≤ 14
Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
It may be 1^4 ............................
Answer:
49°
Step-by-step explanation:
The given information that BC=DC tells you triangle BCD is an isosceles triangle and that angle y is one of the two equal base angles. Then ...
y + y + 82 = 180 . . . . . the sum of angle measures is 180 degrees
2y = 98 . . . . subtract 82
y = 49 . . . . . divide by 2
The measure of y is 49°.