3.9*10 = 39 then that to the 20 power is 6.626621133E31
Hope this helps!
Answer:
Well in set A, all of the sides are the same length but they are different shapes.
In set B, all of the angles are the same, they are just differnet shapes.
Hope this helps! :)
Hello,
2(l+w)=78
Divided 2 from both side
2(l+w)/2=78/2
l+w=39 feet
l=6w+4
Replace l with 6w+4
6w+4+w=39
7w+4=39
Subtract 4 from both side
7w=35
Divided 7 from both side
w=5 feet
l=6w+4
l=6(5)+4
l=30+4
l=34 feet. As a result, the length of the rectangle is 34 feet and the width of rectangle is 5 feet. Hope it help!
Answer:
27 miles.
Step-by-step explanation:
Here I attach the draw of the coordinates.
Tony traveled 3 segments. The first was from (12,6) to (12, 15), where, leting 12 constant, he moved from 6 to 15 in the ordinates axis, which implies 9 units. This is the section 1 in the draw.
Then he moved from point B to C. If you notice, this distance is the hypotenuse on the the triangle DBC. We can find this value using Pitagoras' theorem:
DB^2 + CD^2 = CB^2
With DB=15 and CD=8 (12 minus 4 = 8)
15^2 + 8^2 = 289
So CB^2=289
Applying sqr root:
CB = 17
So, the second section has a measure of 17 units.
Finally, the 3rd section is the hypotenuse of the DAC triangle and we can use Pitagoras to solve it:
CD^2 + AD^2 = CA^2
8^2 + 6^2 = CA^2
64 + 36 = 100
So, CA=10
In the 3r section we traveled 10 units.
So, in total he traveled 10 + 17 + 9 = 36 units
As every unit is 0.75 miles he traveled 36*0.75 miles:
36*0.75 = 27 miles
He traveled in total 27 miles!!
10.417 rounded to the nearest hundredth = 10.42