Answer:
D
Step-by-step explanation:
out of the choices
A) 2x-y=-2
3x+2y=-10
B) x+4y=3
2x+5y=3
C) 2x+3y=5
x-4y=-14
D) 3x+4y=15
x+y=5
only the system in D has a solution of x=5 and y=0
solve by substitution x+y=5 so x=5-y
plug into the other equation so 3(5-y)+4y=15
distribute 15-3y+4y=15 then minus 15 on both sides and combine like terms
so y=0 then put that value back into the other equation
so x+y=5 equals x+0=5 so x=5 this means the solution to the system of equations is the point (5,0)
Hope this helps! :)
Enter a problem...
Calculus Examples
Popular Problems Calculus Find the Domain and Range f(x)=5x-3
f
(
x
)
=
5
x
−
3
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
Interval Notation:
(
−
∞
,
∞
)
Set-Builder Notation:
{
x
|
x
∈
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The range is the set of all valid
y
values. Use the graph to find the range.
Interval Notation:
(
−
∞
,
∞
)
Set-Builder Notation:
{
y
|
y
∈
R
}
Determine the domain and range.
Domain:
(
−
∞
,
∞
)
,
{
x
|
x
∈
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}
Range:
(
−
∞
,
∞
)
,
{
y
|
y
∈
R
}
Answer:
So first you have to do 12-2 since it's in parenthesis. It is 10. 5+4 is 9, and 9 times 10 is 90. 3 squared is 9, then you divide 90 by 9. The answer is 10.
Answer with explanation:
It is given that, there is positive correlation between drinking coconut milk and eating potato chips.
→Correlation coefficient is denoted by r.
→The value of r lies between , -1 and 1 which is represented as , -1 ≤r≤1.
→Correlation that is relation between two variables is said to be strongly positive, if r is equal to 1, and it is said to be strongly weak, if it is equal to -1 , and said to have no association if r=0.
→ The meaning of positive correlation is that value of r, is greater than >0.8 but less than 1.
The two variables which are positively correlated ,can have following relationship.
1. With increase in one other increases.
2.With decrease in one other decreases.
3. Slope will be a linear that is a straight line not passing through origin.
