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Ivanshal [37]
2 years ago
9

A(n) ________ is a hard outside covering that is used for protection and prevents the inner body area from drying out.

Biology
1 answer:
Artist 52 [7]2 years ago
6 0

The cuticle is the most exterior layer of arthropods' tegument, and its principal function is to protect the body and avoid dehydration. Option C is correct. Cuticle.

<h3>What is the cuticle?</h3>

The cuticle is the most exterior layer of arthropods' tegument. It is secreted by the epidermis and develops right over it.

It is composed of two main layers,

  • epicuticle ⇒ outermost layer
  • procuticle ⇒ inner layer

The cuticle is mainly made of chitin, and its function is to protect the organism's body and avoid dehydration.

Because it avoids dehydration it is believed that arthropods had such an evolutive and adaptative successful in their transition from water to the land.

The cuticle also provides support to the body and a muscle attachment surface.

The correct option is C. Cuticle

A _<u>Cuticle</u>_ is a hard outside covering that is used for protection and prevents the inner body area from drying out.

You can learn more about cuticle at

brainly.com/question/3997730

#SPJ1  

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Two linked genes, A and B, are separated by 18 cM. A man with genotype AB/ab marries a woman who is ab/ab. The man’s father was
kolbaska11 [484]

Answer:

a) 9%.  

b) 16.8%.

Explanation:

a).

We are provided with the information that Two linked genes, A and B, are separated by 18 cM (centiMorgan). i.e the recombinant frequency is 18%

Also , the man's genotype is AB/ab... This only result to one explanation, that The man will definitely produce 18% of recombinant gametes which entails

9% Ab & 9% aB

i.e 0.09 Ab & 0.09 aB

On the other-hand, The mother ab/ab have tendency to produce just one single type of gamete which is ab

∴

The probability that their first child will be Ab/ab will be

Pr ( Ab/ab) = (0.09) x (1)

= 0.09

= 9%.  

b).

If the father produces 18% of recombinant gametes which entails

9% Ab & 9% aB , this typically implies that the number of the non-recombinant gametes will be;

100%-18% = 82%  ( non-recombinant gametes)

i.e genotype AB/ab = 82%

AB =41%; ab = 41%

AB = 0.41 ; ab = 0.41

Now, the probability that their first two children will both be ab/ab:

Using Multiplication Rule to calculate the probability that their first two children (ab/ab); we have:

 (0.41)(1) ×(0.41)(1)

= 0.1681

= 16.8%.

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