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nalin [4]
3 years ago
13

A student isolates, purifies, and combines in a test tube a variety of molecules needed for DNA replication. After adding some D

NA to the mixture, replication occurs, but each DNA molecule consists of a normal strand paired with numerous segments of DNA a few hundred nucleotides long. What has the student probably left out of the mixture
Biology
1 answer:
aivan3 [116]3 years ago
4 0

Answer:

DNA ligase

Explanation:

DNA replication is an enzyme mediated, 3-step process during which the DNA molecule produces a copy of itself. The 3 steps involved are as follows;

  • initiation
  • elongation
  • termination

<em>Initiation </em>involves the unwinding of the double helix structure of the DNA using DNA helicase enzyme

<em>Elongation</em> involves binding of RNA primer to the DNA strands and addition of bases to the primer<em> </em>to elongate the new chains. Bases are added to the leading strand continuously while the lagging strand is replicated in short segments (okazaki segments).

<em>Termination</em> involves the unbinding of RNA primer and substitution of its bases by DNA bases. The Okazaki fragments are then joined together using the DNA ligase enzyme.

<em>The short, numerous segments of DNA observed in the mixture is the Okazaki fragments of the lagging strand. This is due to the absence of the enzyme involved in the joining of these fragments.</em>

Hence, the answer is DNA ligase.

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Eva8 [605]

Answer:

0.17 mole of glucose is formed.

Explanation:

Step 1:

The equation for the reaction. This is given below:

CO2 + H2O —> C6H12O6 + O2

Step 2:

Balancing the equation.

The equation can be balanced as follow:

CO2 + H2O —> C6H12O6 + O2

There are 6 atoms of C on the right side and 1 atom on the left side. It can be balance by putting 6 in front of CO2 as shown below:

6CO2 + H2O —> C6H12O6 + O2

Therefore are 12 atoms of H on the right side and 2 atoms on the left side. It can be balance by putting 6 in front of H2O as shown below:

6CO2 + 6H2O —> C6H12O6 + O2

There are a total of 8 atoms of O the right side and a total of 18 atoms on the left. It can be balance by putting 6 in front of O2 as shown below:

6CO2 + 6H2O —> C6H12O6 + 6O2

Now the equation is balanced.

Step 3:

Determination of the number of mole of glucose (C6H12O6) produced by 1 mole of water.

This is illustrated below:

6CO2 + 6H2O —> C6H12O6 + 6O2

From the balanced equation above,

6 moles of H2O produced 1 mole of C6H12O6.

Therefore, 1 mole of H2O will produce = 1/6 = 0.17 mole of C6H12O6.

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