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2 years ago

I need help with 7 and 4 and 9 also 10 I will give the most higher points I got

Mathematics

1 answer:

Serga [27]2 years ago

8 0

7. 9/5 = 1 4/5
*When multiplying with a whole number u can turn it into a fraction by putting a one under it
So 3/1 times 3/5 = 9/5
*just multiply straight across

4. 2/1 times 1/4 = 2/4 = THEN SIMPLIFY = 1/2

9. 3/4 times 3/1 (cups)
*multiply straight across
9/4 = 2 1/4 (cups of sugar)
So she uses less than 3 cups to make all 3 loaves

* 10. Sorry I can’t tell if it says 5/6 on both of them
If it says 5/6 on both of them then the answer is obvious and she worked more than that over the course of 2 days

* 10. It must be a 5/9 on the second one
So if so
5/6 times 2/1 (days)
10/6 then we need to multiply the 6 denominator (bottom of the fraction) with something to = 9 denominator
9 divided by 6 = 1.5
10/6 times 1.5 for both the numerator (top) and denominator (bottom)
= 15/9 (simplified 1 6/9)
This one she exercised more than 5/9

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3. The adult men of the Dinaric Alps have the highest average height of all regions. The

ahrayia [7]

Using the normal distribution, it is found that:

3 - a) The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

3 - b) The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

4 - a) The 25th percentile for the math scores was of 71.6 inches.

4 - b) The 75th percentile for the math scores was of 78.4 inches.

<h3>Normal Probability Distribution </h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

Question 3:

The mean is of 73 inches, hence $\mu = 73$ .

The standard deviation is of 3 inches, hence $\sigma = 3$ .

Item a:

The 40th percentile is X when Z has a p-value of 0.4, so X when Z = -0.253.

$Z = \frac{X - \mu}{\sigma}$

$-0.253 = \frac{X - 73}{3}$

$X - 73 = -0.253(3)$

$X = 72.2$

The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

Item b:

The minimum height is the 100 - 10 = 90th percentile is X when Z has a p-value of 0.9, so X when Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 73}{3}$

$X - 73 = 1.28(3)$

$X = 76.84$

The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

Question 4:

The mean score is of 75, hence $\mu = 75$ .

The standard deviation is of 5, hence $\sigma = 5$ .

Item a:

The 25th percentile is X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 75}{5}$

$X - 75 = -0.675(5)$

$X = 71.6$

The 25th percentile for the math scores was of 71.6 inches.

Item b:

The 75th percentile is X when Z has a p-value of 0.25, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 75}{5}$

$X - 75 = 0.675(5)$

$X = 78.4$

The 75th percentile for the math scores was of 78.4 inches.

To learn more about the normal distribution, you can take a look at brainly.com/question/24663213

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Step-by-step explanation:

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$(-8)(-\frac{2}{3})$

You can idenfity that both factors are negative. Then, the product (The result of the multiplication) will be positive.

Then, in order to get the product, you need to multiply the numerator of the fraction by -8. So, you get:

$\frac{(-2)(-8)}{3}=\frac{16}{3}$

You can notice that the numerator and the denominator of the fraction obtained cannot be divided by the same number; therefore, the fraction cannot be simplified.

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