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Setler [38]
2 years ago
13

Select the statement below that correctly describes the relationship between the number of workers and the hours that they work.

Mathematics
1 answer:
oee [108]2 years ago
6 0

Less workers = more hours

OR the answer might be worded as

More workers = less hours

You might be interested in
Solve for x. 2 1/2x − 3/4 (2x+5) = 38 ASAP
svetoff [14.1K]

Answer:

  x = 41 3/4

Step-by-step explanation:

(2 1/2)x -(3/4)(2x +5) = 38

(2 1/2)x -(1 1/2)x -15/4 = 38 . . . . use the distributive property

x = 38 +3 3/4 . . . . . . add 15/4

x = 41 3/4

_____

Another way to solve this is to "clear fractions" by multiplying the whole equation by 4:

  10x -3(2x +5) = 152

  4x -15 = 152 . . . . eliminate parentheses

  4x = 167 . . . . . . . add 15

  x = 41 3/4 . . . . . . divide by 4

7 0
3 years ago
Suppose a system of linear equations has a 3 5 augmented matrix whose fifth column is a pivot column. is the system consistent?
likoan [24]

Answer:

The system will be inconsistent.

Step-by-step explanation:

We are given that a system of linear equations has a 3×5 augmented matrix whose fifth column is a pivot column.

Then such a system is not consistent because since the augmented matrix has a pivot in fifth column it means that the new column added to the matrix A will lead to increase in the rank as that of matrix  A.

Hence the rank of A and Augment A will not remain same and hence the system will be inconsistent.

7 0
3 years ago
444. IU
murzikaleks [220]

Answer:

That is the third one :

456.222

because it has the most numbers 4,5,6 and point . 2,2,2

3 0
3 years ago
Math help please,,, thank u uwu!
Svetlanka [38]

Answer:

AC=BD

CAD=CBD

ACB=ADB

Step-by-step explanation:

You're essentially looking for anything of equal proportions. Obviously, your circle is split by several lines, and each side is symmetric. Since you know this, it's simply a matter of identifying one element then finding its symmetric match.

Follow the lines and trace the path with your finger for each question. If you do this, you'll see that AC=BD is an answer that involves a symmetric pair, because these two are equal distances and equal (but opposite) in placement.

Continuing with this method, keep track of the parts of the triangles you trace. With CAD=CBD, you trace across a hypotenuse, a leg, and a base in BOTH, making this true.

Continuing further with ACB=ADB, you trace across a hypotenuse, a leg, and a base with both AGAIN, making this true.

With AB=CD, this is obviously incorrect. You can't jump between points.

7 0
3 years ago
Read 2 more answers
Consider the integral Integral from 0 to 1 e Superscript 6 x Baseline dx with nequals 25 . a. Find the trapezoid rule approximat
photoshop1234 [79]

Answer:

a.

With n = 25, \int_{0}^{1}e^{6 x}\ dx \approx 67.3930999748549

With n = 50, \int_{0}^{1}e^{6 x}\ dx \approx 67.1519320308594

b. \int_{0}^{1}e^{6 x}\ dx \approx 67.0715427161943

c.

The absolute error in the trapezoid rule is 0.08047

The absolute error in the Simpson's rule is 0.00008

Step-by-step explanation:

a. To approximate the integral \int_{0}^{1}e^{6 x}\ dx using n = 25 with the trapezoid rule you must:

The trapezoidal rule states that

\int_{a}^{b}f(x)dx\approx\frac{\Delta{x}}{2}\left(f(x_0)+2f(x_1)+2f(x_2)+...+2f(x_{n-1})+f(x_n)\right)

where \Delta{x}=\frac{b-a}{n}

We have that a = 0, b = 1, n = 25.

Therefore,

\Delta{x}=\frac{1-0}{25}=\frac{1}{25}

We need to divide the interval [0,1] into n = 25 sub-intervals of length \Delta{x}=\frac{1}{25}, with the following endpoints:

a=0, \frac{1}{25}, \frac{2}{25},...,\frac{23}{25}, \frac{24}{25}, 1=b

Now, we just evaluate the function at these endpoints:

f\left(x_{0}\right)=f(a)=f\left(0\right)=1=1

2f\left(x_{1}\right)=2f\left(\frac{1}{25}\right)=2 e^{\frac{6}{25}}=2.54249830064281

2f\left(x_{2}\right)=2f\left(\frac{2}{25}\right)=2 e^{\frac{12}{25}}=3.23214880438579

...

2f\left(x_{24}\right)=2f\left(\frac{24}{25}\right)=2 e^{\frac{144}{25}}=634.696657835701

f\left(x_{25}\right)=f(b)=f\left(1\right)=e^{6}=403.428793492735

Applying the trapezoid rule formula we get

\int_{0}^{1}e^{6 x}\ dx \approx \frac{1}{50}(1+2.54249830064281+3.23214880438579+...+634.696657835701+403.428793492735)\approx 67.3930999748549

  • To approximate the integral \int_{0}^{1}e^{6 x}\ dx using n = 50 with the trapezoid rule you must:

We have that a = 0, b = 1, n = 50.

Therefore,

\Delta{x}=\frac{1-0}{50}=\frac{1}{50}

We need to divide the interval [0,1] into n = 50 sub-intervals of length \Delta{x}=\frac{1}{50}, with the following endpoints:

a=0, \frac{1}{50}, \frac{1}{25},...,\frac{24}{25}, \frac{49}{50}, 1=b

Now, we just evaluate the function at these endpoints:

f\left(x_{0}\right)=f(a)=f\left(0\right)=1=1

2f\left(x_{1}\right)=2f\left(\frac{1}{50}\right)=2 e^{\frac{3}{25}}=2.25499370315875

2f\left(x_{2}\right)=2f\left(\frac{1}{25}\right)=2 e^{\frac{6}{25}}=2.54249830064281

...

2f\left(x_{49}\right)=2f\left(\frac{49}{50}\right)=2 e^{\frac{147}{25}}=715.618483417705

f\left(x_{50}\right)=f(b)=f\left(1\right)=e^{6}=403.428793492735

Applying the trapezoid rule formula we get

\int_{0}^{1}e^{6 x}\ dx \approx \frac{1}{100}(1+2.25499370315875+2.54249830064281+...+715.618483417705+403.428793492735) \approx 67.1519320308594

b. To approximate the integral \int_{0}^{1}e^{6 x}\ dx using 2n with the Simpson's rule you must:

The Simpson's rule states that

\int_{a}^{b}f(x)dx\approx \\\frac{\Delta{x}}{3}\left(f(x_0)+4f(x_1)+2f(x_2)+4f(x_3)+2f(x_4)+...+2f(x_{n-2})+4f(x_{n-1})+f(x_n)\right)

where \Delta{x}=\frac{b-a}{n}

We have that a = 0, b = 1, n = 50

Therefore,

\Delta{x}=\frac{1-0}{50}=\frac{1}{50}

We need to divide the interval [0,1] into n = 50 sub-intervals of length \Delta{x}=\frac{1}{50}, with the following endpoints:

a=0, \frac{1}{50}, \frac{1}{25},...,\frac{24}{25}, \frac{49}{50}, 1=b

Now, we just evaluate the function at these endpoints:

f\left(x_{0}\right)=f(a)=f\left(0\right)=1=1

4f\left(x_{1}\right)=4f\left(\frac{1}{50}\right)=4 e^{\frac{3}{25}}=4.5099874063175

2f\left(x_{2}\right)=2f\left(\frac{1}{25}\right)=2 e^{\frac{6}{25}}=2.54249830064281

...

4f\left(x_{49}\right)=4f\left(\frac{49}{50}\right)=4 e^{\frac{147}{25}}=1431.23696683541

f\left(x_{50}\right)=f(b)=f\left(1\right)=e^{6}=403.428793492735

Applying the Simpson's rule formula we get

\int_{0}^{1}e^{6 x}\ dx \approx \frac{1}{150}(1+4.5099874063175+2.54249830064281+...+1431.23696683541+403.428793492735) \approx 67.0715427161943

c. If B is our estimate of some quantity having an actual value of A, then the absolute error is given by |A-B|

The absolute error in the trapezoid rule is

The calculated value is

\int _0^1e^{6\:x}\:dx=\frac{e^6-1}{6} \approx 67.0714655821225

and our estimate is 67.1519320308594

Thus, the absolute error is given by

|67.0714655821225-67.1519320308594|=0.08047

The absolute error in the Simpson's rule is

|67.0714655821225-67.0715427161943|=0.00008

6 0
3 years ago
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