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Olegator [25]
3 years ago
5

Please help with these two, or one I will give brainly for correct answer no bots or links

Mathematics
1 answer:
scoray [572]3 years ago
3 0
You multiple the area 18 x 12 = 96 sq ft
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Evaluate the given expression if x = 25, y = 10, w = 11, and z = 18.<br><br> (see the image)
hammer [34]

Answer:

D

Step-by-step explanation:

So we have the expression:

(x-y)^2+10wz

And we want to evaluate it when x=25, y=10, w=11, and z=18.

So, substitute these values for the variables:

=(25-10)^2+10(11)(18)

First, subtract within the parentheses:

=(15)^2+10(11)(18)

Square 15:

=225+10(11)(18)

Now, multiply the terms on the right. 10 times 11 is 110:

=225+110(18)

Multiply:

=225+1980

Finally, add:

=2205

So, our answer is D.

And we're done!

8 0
3 years ago
Read 2 more answers
160 bananas;20%decrease
Jobisdone [24]

Answer:

128 banana's... I would work it all out for u but the teacher just came in my room and had a go

7 0
2 years ago
Read 2 more answers
What is an equation of the line that passes through the point ( 6 , − 2 ) (6,−2) and is perpendicular to the line 6 x + y = 2 6x
Diano4ka-milaya [45]

Answer:

An equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

  • y=\frac{1}{6}x-3

Step-by-step explanation:

We know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept.

Given the line

6x+y=2

Simplifying the equation to write into the  slope-intercept form

y = -6x+2

So, the slope = -6

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line.

Thus, the slope of the perpendicular line will be: -1/-6 = 1/6

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be

y-y_1=m\left(x-x_1\right)

substituting the values m = 1/6 and the point (6, -2)

y-\left(-2\right)=\frac{1}{6}\left(x-6\right)

y+2=\frac{1}{6}\left(x-6\right)

subtract 2 from both sides

y+2-2=\frac{1}{6}\left(x-6\right)-2

y=\frac{1}{6}x-3

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

  • y=\frac{1}{6}x-3
5 0
3 years ago
A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose pe
soldier1979 [14.2K]

Using the normal distribution, it is found that:

a) 0.8599 = 85.99% probability that x is more than 60.

b) 0.1788 = 17.88% probability that x is less than 110.

c) 0.6811 = 68.11% probability that x is between 60 and 110.

d) 0.0643 = 6.43% probability that x is greater than 125.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of 87, thus \mu = 87.
  • The standard deviation is of 25, thus \sigma = 25.

Item a:

This probability is <u>1 subtracted by the p-value of Z when X = 60</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 87}{25}

Z = -1.08

Z = -1.08 has a p-value of 0.1401.

1 - 0.1401 = 0.8599

0.8599 = 85.99% probability that x is more than 60.

Item b:

This probability is the <u>p-value of Z when X = 110</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 87}{25}

Z = 0.92

Z = 0.92 has a p-value of 0.8212.

1 - 0.8212 = 0.1788.

0.1788 = 17.88% probability that x is less than 110.

Item c:

This probability is the <u>p-value of Z when X = 110 subtracted by the p-value of Z when X = 60</u>.

From the previous two items, 0.8212 - 0.1401 = 0.6811.

0.6811 = 68.11% probability that x is between 60 and 110.

Item d:

This probability is <u>1 subtracted by the p-value of Z when X = 125</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{125 - 87}{25}

Z = 1.52

Z = 1.52 has a p-value of 0.9357.

1 - 0.9357 = 0.0643.

0.0643 = 6.43% probability that x is greater than 125.

A similar problem is given at brainly.com/question/24863330

7 0
3 years ago
What is the approximate area of the shaded sector in the circle shown below?
stich3 [128]

Answer: 26.5cm2

Step-by-step explanation:

4 0
3 years ago
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