The range of the function y = 4x + 2 where the domain is the set of all of
the positive even numbers less than 10 is {10, 18, 26, 34}
The given equation is:
y = 4x + 2
The domain is the set of all of the positive even numbers less than 10.
That is, x = {2, 4, 6 ,8}
To get the range, find the values of y for x = 2, 4, 6, and 8
For x = 2:
y = 4(2) + 2
y = 8 + 2
y = 10
For x = 4:
y = 4(4) + 2
y = 16 + 2
y = 18
For x = 6:
y = 4(6) + 2
y = 24 + 2
y = 26
For x = 8:
y = 4(8) + 2
y = 32 + 2
y = 34
Therefore, the range = {10, 18, 26, 34}
Learn more here: brainly.com/question/18479953
Answer:
last option
Step-by-step explanation:
To prove that ΔEFG is also a right triangle, you must prove that KL = EF so that in ΔKLM c² = a² + b² which would make ΔEFG a right triangle.
Answer:
she had 6 more iris bloom this year
Step-by-step explanation:
40 times .15 is 6
Answer:
Step-by-step explanation:
I'm goig to assume that the formula we need here is the following:
where A(t) is the amount in the account after the compounding is done, n is the number of times per year the compounding occurs, r is the rate in decimal form, and t is the time in years. Filling in accordingly,
and simplifying a bit,
and simplifying a bit more,
A(t) = 90000(1.343916379) so
the amount in the account after 5 years is
A(t) = 120,952.47
Answer:
y = -2(x + 1)^2 + 8
Step-by-step explanation:
The equation of a parabola can be written in the form;
y = a(x-h)^2 + k
where a is the multiplier (h,k) is the vertex
so h = -1 and k = 8
Plug in these values
y = a(x + 1)^2 + 8
So to get the value of a, we use the point where the parabola passes through which is the point (1,0)
Simply substitute the values of x and y
0 = a(1 + 1)^2 + 8
0 = a(2)^2 + 8
-8 = 4a
a = -8/4
a = -2
So therefore the equation of the parabola is ;
y = -2(x + 1)^2 + 8
