Answer:
When x = 4, (4, 0)
When y = 4, (6, 4)
Step-by-step explanation:
To find the ordered-pair solution when x = 4, plug 4 into the x of the equation.
y = 2x - 8
y = 2(4) - 8
y = 8 - 8
y = 0
This produces the ordered pair (4, 0).
To find the ordered-pair solution when y = 4, plug 4 into the y of the equation.
y = 2x - 8
4 = 2x - 8
12 = 2x
6 = x
x = 6
This produces the ordered pair (6, 4).
Answer:
45
Step-by-step explanation:
When you're completing the square you're adding (b/2)^2 which in this case is (-5)^2 or 25. This is because when you rewrite it as a square binomial you write it in the form (x+(b/2))^2 which is going to result in x^2+b+(b/2)^2. Since you need to reach 25 you need to add 45 since the last value is at -20.
Answer:
I dont k ow what the following set for your equation is...
Answer:
x = 17 and y = 37
Step-by-step explanation:
Let the numbers be x and y.
y = 3 + 2x
xy = 629
substituting y in the second equation we get
x(3+2x) = 629
3x + 2
= 629
2
+ 3x - 629 = 0
Solving a quadratic equation by using its formula:
x = [-3 ±√(9-4(2)(-629)] / 4
x = [-3 ± √5041] / 4
x = [-3 ± 71] / 4
x = 17 and 
Ignore the negative number in x and just use x = 17 in the first equation we get
y = 3 + 2(17) = 37