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mr Goodwill [35]
3 years ago
15

Noah manages a buffet at a local restaurant. He charges $10 for the buffet. On average, 16 customers choose the buffet as their

meal every hour. After surveying several customers, Noah has determined that for every $1 increase in the cost of the buffet, the average number of customers who select the buffet will decrease by 2 per hour. The restaurant owner wants the buffet to maintain a minimum revenue of $130 per hour. Noah wants to model this situation with an inequality and use the model to help him make the best pricing decisions. Assuming that any increase occurs in whole dollar amounts, what is the maximum possible increase that maintains the desired minimum revenue? Explain why this is true.

Mathematics
1 answer:
kicyunya [14]3 years ago
8 0

Answer:

$3 max

Step-by-step explanation:

Charge= b, Customer= c, Revenue= r

r= bc, currently, r= 16*10= $160

We know that: b+1 ⇒ c-2  and the target is r ≥ 130

So, this will all be reflected as:

b=10+x ⇒ c= 16-2x

  • (10+x)(16-2x) ≥ 130
  • 160 -20x +16x - 2x² ≥ 130
  • -2x² - 4x + 30 ≥ 0
  • x² + 2x -15 ≤ 0
  • (x+1)² ≤ 4²
  • x+1 ≤ 4 (negative value not considered)
  • x ≤ 3

As we see the max increase amount is $3, when the revenue will be:

(10+3)*(16-3*2)= 13*10= $130

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Answer:

⇒ Add 8x to both sides of the inequality

⇒ x>1/5

Step-by-step explanation:

First, you subtract by 5 from both sides of equation.

5-8x-5<2x+3-5

Solve.

-8x<2x-2

Then subtract by 2x from both sides of equation.

-8x-2x<2x-2-2x

Solve.

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Multiply by -1 from both sides of equation.

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Solve.

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Divide by 10 from both sides of equation.

10x/10>2/10

Solve to find the answer.

2/10=10/2=5 2/2=1=1/5

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Hope this helps!

5 0
3 years ago
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ladessa [460]

Answer:

B. 1.83\text{ m}^2

Step-by-step explanation:

We are asked to find the body surface area of a person whose height is 150 cm and who weighs 80 kg.

\text{Body surface area}( m^2)=\sqrt{\frac{\text{Height (cm)}\times \text{Weight (kg)}}{3600}}

Substitute the values:

\text{Body surface area}( m^2)=\sqrt{\frac{150\text{ cm}\times 80\text{(kg)}}{3600}}

\text{Body surface area}( m^2)=\sqrt{\frac{12,000}{3600}}

\text{Body surface area}( m^2)=\sqrt{3.3333333}

\text{Body surface area}( m^2)=1.825741

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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We can simplify this to:

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