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3 years ago

If I make $14.00 an hour how much will I make monthly?

2 answers:

6 0

Well, you earn 14x dollars per month, where x is the number of hours you work every month. All you need to do is multiply 14 times the number of hours you work every month.

Please consider marking this answer as Brainliest to help me advance.

sweet [91]3 years ago

4 0

Answer:

Step-by-step explanation:

If you are making $14.00 in an hour then in 1 day it will be $14.00 × 24 = $336.00 and in 1 month $336.00 × 12 = <u>$4032.00</u>

You might be interested in

How do I simplify 9v+9(1+7v) and can you show me the work

KonstantinChe [14]

Answer:72v+9

Step-by-step explanation:

Apply the distributive property.

9 v + 9 ⋅ 1 + 9 ( 7 v )

Multiply

9 by 1 . 9 v + 9 + 9 ( 7 v )

Multiply

7 by 9 . 9 v + 9 + 63 v

Add

9 v and 63 v . 72 v + 9

I hope this helps you.

7 0

3 years ago

What is the measurement

Blizzard [7]

Answer:

X=135 degrees

Step-by-step explanation:

the total interior angle of a triangle is 180.

To work this out you would first add the interior angles of B which is 69 and the interior angle of C which is 66, which gives you 135.

The next step is to minus 135 from 180, which gives you 45. This is because the total interior angle of a triangle is 180.

Then to work out the angle of x you would minus 45 from `180, which gives you 135. This is because the total angle in a straight line is 180 degrees.

1) Add the angles of 69 and 66.

$69+66=135\\$

2) Minus 135 from 180.

$180-135=45$

3) Minus 180 from 45.

$180-45=135 degrees$

3 0

3 years ago

How many solutions does 6x−1=34−x have

aleksley [76]

Step-by-step explanation:

6x+x=34+1

7x=35

x=35/7

x=5

Hence this equation has only one solution

4 0

2 years ago

Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)

UkoKoshka [18]

Since the limit becomes the undetermined form

$\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}$

it means that both polynomials have a root at $x=1$ . So, we can fact both numerator and denominator:

$x^3-2x^2+3x-2 = (x-1)(x^2-x+2)$

$2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)$

So, the fraction becomes

$\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}$

Now, as x approaches 1, you have no problems anymore:

$\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}$

4 0

3 years ago

I need this please help me

kherson [118]

Answer:

I attached a picture of the completed picture below.

The values given to you in the picture are shown in pink

Use those values to fill in the rest, which are shown in blue.

6 0

2 years ago