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Stels [109]
3 years ago
13

What are the solutions to m^2 – 9 = 0? a. m = –9 and m = 0 b. m = –3 and m = 3 c. m = –3 d. m = 9

Mathematics
1 answer:
marysya [2.9K]3 years ago
5 0
2 ways
zero product property
easy way

zero product
factor perfect square
m^2-3^2=0
(m-3)(m+3)=0
set each to zero
m-3=0
x=3

m+3=0
m=-3

m=-3 or 3

easy way
add 9 to both sides
m^2=9
sqrt both sides remember to take postive and negative roots
m=+/-3
m=-3 or 3


B is answer

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3 years ago
Can you help me graph and list the (Zeros, Maximums, Minimums, Asymptotes)
Marina86 [1]

The zero of the function is at 33.69 degree , the graph is plotted and attached with the answer.

<h3>What is a Function ?</h3>

A function is a law that relates a dependent variable and an independent variable with each other

It is given that

y = 2tan (x - π/2) +3

To find the zeroes of a function that function has to be equated to zero.

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2tan (x - π/2)  = -3

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x = 33.69 degree

The zero of the function is at 33.69 degree

For finding the maxima /minima

the derivative is

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the point at which the slope is zero is substituted in the second derivative to find maxima/minima

d²y/dx² = 4 sec² (x - π/2) tan (x - π/2)

if the value is negative then it is a maxima and if it is positive it is a minima.

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x = 0+ πn

No horizontal or oblique asymptote

To know more about Function

brainly.com/question/12431044

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2 years ago
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