Answer:
anything smaller than their sum, which is larger than their difference:
33-32-31-30-29-28-27-26-25-24-23-22-21-20-19-18-17-16-15-14-13-12-11-10-9-8-7
Mean number of errors in each page = 0.01
Mean number of errors in 100 pages = 0.01*100=1
It is possible to use the cumulative distribution function (CMF), but the math is a little more complex, involving the gamma-function. Tables and software are available for that purpose.
Thus it is easier to evaluate with a calculator for the individual cases of k=0,1,2 and 3.
The Poisson distribution has a PMF (probability mass function)


with λ = 1
=>




=>

or
P(k<=3)=
0.9810 (to four decimal places)
Only <span>set Y = {6, 24, 36, 78, 84}, contains only whole numbers divisible by 6.
There were no options but this was the answer to this question on a quiz.
hope this helps!</span>
Answer:
-13
Step-by-step explanation:
The more negative the number, the colder it is
-13 is more negative than -10
-13 < -10
-13 is colder