We are looking for the inner perimeter of the track. Since there are two semicircles, these mix to form one full circle so we can use the formula to find the circumference of the circle with a diameter of 60 m, which was given to us. With a diameter of 60m, the radius will be 30m. Now we can solve this problem.
C = 2πr
C = 2π(30)
C = 60π
The semicircle ends of the track are a distance of 60π m, and now we just need to add the lengths of the inner track which are 100 m each. So:
P = 60π + 100m + 100m
P = 200 + 60π
P = 388.5 m
i got 28cm.... But im not sure
The two 3s have different place values. The 3 on the left is in thousands place while the 3 on the right is in the ones place. we can also look at this vc by separating each digit ( 3000 + 400 + 50 + 3)
while the digits are the same, their place determines the value
So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
Thus, the dimensions of the rectangle are 15cm by 11cm
Answer:
you might have to use an app that scans that specific problem :)
Step-by-step explanation:
