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skelet666 [1.2K]
2 years ago
5

Find the solution to the system of equations x + y = 9 and x - y = -1.

Mathematics
2 answers:
Galina-37 [17]2 years ago
6 0

Answer:

(4, 5 )

Step-by-step explanation:

x + y = 9 → (1)

x - y = - 1 → (2)

adding the 2 equations term by term will eliminate y

2x + 0 = 8

2x = 8 ( divide both sides by 2 )

x = 4

substitute x = 4 into either of the 2 equations and solve for y

substituting into (1)

4 + y = 9 ( subtract 4 from both sides )

y = 5

solution is (4, 5 )

DerKrebs [107]2 years ago
3 0
Answer: x = 4, y = 5

Step-by-Step Explanation:

=> x + y = 9 (Eq. 1)
=> x - y = -1 (Eq. 2)

Lets Solve by Elimination Method.

Adding Eq. 1 and Eq. 2, we get :-

2x = 9 - 1
2x = 8
x = 8/2
=> x = 4

Therefore, x = 4

Substitute value of ‘x’ in Eq. 1 :-

x + y = 9
4 + y = 9
y = 9 - 4
=> y = 5

Therefore, y = 5

Hence, x = 4 and y = 5 (4, 5)
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Read 2 more answers
QUESTION 1 Evaluate −30 ÷ −6. a 5 b −5 c 6 d −6 QUESTION 2 Evaluate 62 ÷ (3 + 9). a3 b4 c12 d21 QUESTION 3 Danny made a mistake
Mashcka [7]

Answer:

A; ?; Line 3

Step-by-step explanation:

Question 1:

-30 divided by -6 is 5.

The negatives cancel each other out.

And 30 divided by 6 is simply 5.

Question 2:

62\div(3+9)

Do the operation inside the parenthesis first:

62\div12

Divide. 12 does not go into 62 evenly. 12 times 5 is 60, so the answer is 5 remainder 2:

62\div12=5\text { R}2

Or in fractions:

31/6

(Was there a typo? From what you've given me, the correct answer is not listed.)

Question 3:

So we have to following steps:

\text{Line 1: } 21+35\div7+6(2)\\\text{Line 2: }21+5+6(2)\\\text{Line 3: }21+11(2)\\\text{Line 4: }21+22\\\text{Line 5: }43

The mistake is in Line 3. Danny cannot just combine 5+6(2) into 11(2). Instead, he should multiply 6(2) and then add. Thus, the correct solution is:

\text{Line 1: } 21+35\div7+6(2)\\\text{Line 2: }21+5+6(2)\\\text{Line 3: }21+5+12\\\text{Line 4: }26+12\\\text{Line 5: }38

3 0
3 years ago
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