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Julli [10]
3 years ago
13

I don’t get number 6

Mathematics
2 answers:
IgorLugansk [536]3 years ago
4 0
I think you just do 5x40 and you get 200
blondinia [14]3 years ago
4 0
5 times 40 which equals 200 is the answer
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. Sara collected $135 in donations for the hospital. This represents 5% of the total amount collected by her class. How much did
AfilCa [17]
5 percent of 2700 is 135 so the answer is $2700

6 0
3 years ago
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Explain how to find the zeros of the given polynomial: x3+3x2–x−3<br><br> What are the zeros?
AveGali [126]

Answer:

Step-by-step explanation:

The zero (root) of a function is any value of the variable that will produce an answer of zero. Graphically, the real zero of a function is where the graph of the function crosses the x-axis.

~~~~~~~~~

f(x) = x³ + 3x² - x - 3

f(-3) = ( - 3 )³ + 3( - 3 )² - ( - 3 ) - 3 = 0

f(-1) = ( - 1 )³ + 3( - 1 )² - ( - 1 ) - 3 = 0

f(1) = ( 1 )² + 3( 1 )² - ( 1 ) - 3 = 0

3 0
3 years ago
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Tom earns ​$12 a week mowing lawns. He spends
Gnoma [55]

Answer:

6 dollars on lunch because 36 divided by 6 is 6 lol and you should multiply 1/3 to 2/6 to have an even number so it would be 12 on music and 6 on lunch so 18 total spent and 18 saved

18 total saved

Step-by-step explanation:

8 0
3 years ago
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I need graph help plz ​
Likurg_2 [28]

Answer:

Step-by-step explanation:

Part A

x-intercepts of the graph → x = 0, 6

Maximum value of the graph → f(x) = 120

Part B

Increasing in the interval → 0 ≤ x ≤ 3

Decreasing in the interval → 3 < x ≤ 6

As the price of goods increase in the interval [0, 3], profit increases.

But in the price interval of (3, 6] profit of the company decreases.

Part C

Average rate of change of a function 'f' in the interval of x = a and x = b is given by,

Average rate of change = \frac{f(b)-f(a)}{b-a}

Therefore, average rate of change of the function in the interval x = 1 and x = 3 will be,

Average rate of change = \frac{f(3)-f(1)}{3-1}

                                         = \frac{120-60}{3-1}

                                         = 30

6 0
3 years ago
Hi what is the answer for this?
saw5 [17]
This is a common factor problem.

Pencils come in a pack of 12
Erasers come in a pack of 10

First, break the number into their prime factors(the idea is that we will break the number down into its smallest multiples, which are prime numbers):
10 = 2 * 5
12 = 2 * 2 *3

So now we take the unique multiples of each number, and when we multiply them together, we will get the smallest number that both 10 and 12 can be divided into(this is what the problem is asking for)
We have (2*2*3) that comes from 12, and the only unique number that comes from the 10 is (5)
So now, we multiply:
2*2*3*5=60
However, this isn't exactly out answer. Now we have to divide our answer by the number of each this in the pack to know how many packs to buy.
60/12=5 packs of pencils
60/10= 6 packs of erasers

I hope this helps. Let me know if you have any questions!!
5 0
3 years ago
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