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Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
Answer:
The probability of NOT hitting a boundary is (4/5).
Step-by-step explanation:
Let E: Be the event of hitting a boundary
now, Probability of any event E = 
Here, number of favorable outcomes = 6
So, P(E) = 
⇒Probability of hitting a six is 1/5
Now, P(E) + P(not E) = 1
So, P(not hitting a boundary ) = 1 - P(hitting a boundary)
= 1 - (1/5) = 4/5
Hence, the probability of NOT hitting a boundary is (4/5).
Answer:
It increases x3.
Step-by-step explanation:
Let's say the fraction to begin with was 100/100. Ignore the fact that it isn't fully reduced and it is an improper fraction.
10% of 100 is 10, so the numerator is now 90 (decrease=get smaller; 100-10=90).
70% of 100 is 70, so the denominator is now 30 (decrease=get smaller; 100-70=30).
Our fraction is now 90/30 which, when fully reduced, equals 3.00. Since 100/100 equals 1.00, it has increased by 2.00 (3x bigger).
Answer:
16
Step-by-step explanation:
(b/2)^2
(8/2)^2 = (4)^2 = 16
(x^2+8x+16) = -3+16
(x+4)^2 = 13
so on so forth, but basically you add 16 which completes the square
