Factor:
2sin^2x-sinx = 0
sinx(2sinx - 1) = 0
Therefore the solutions are when:
sin x = 0
And
sinx = 1/2
So sinx = 0
is true when x = 0 and pi and all the angles coterminal with these points. Thus, the answer is x = pi*n, (where n is some integer)
sinx = 1/2
is true when x = pi/6 and 5pi/6 and the angles coterminal with these points.
Thus, the answer is x = pi/6 + 2pi*n (where n is some integer)
and x = 5pi/6 + 2pi*n (where n is some integer)
Answer:
For the top table:
[x] | 3.1 | 2.5 | 1.2 | 0.9 | 0.14 | 0.06 | 0.02 |
[y] | 15.5 | 12.5 | 6 | 4.5 | 0.7 | 0.3 | 0.1 |
For the bottom table:
k = 5
[x] | 3.1 | 2.5 | 1.2 | 0.9 | 0.14 | 0.06 | 0.02 |
[y] | 15.5 | 12.5 | 6 | 4.5 | 0.7 | 0.3 | 0.1 |
Answer:
5x maybe dont take my word
For A:
You add the probabilities to get the answer to A: = .75, or 3/4
Note that the probability of ALL THREE of them hitting would be 1/3 x 1/4 x 1/5.
For B:
2/3 and 3/4 is the probability of the other two people MISSING (the remainder of 1/3, 1/4)
1.0 = 100% chance to hit the target, so 1.0 x 2/3 x 3/4 = 1/2
Mark's chance of hitting is 1/5, so do 1/2 x 1/5, = 1/10
Step-by-step explanation:
1 Expand by distributing terms.
rx+r×2
2 Regroup terms.
rx+2r
