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2 years ago

11

The value of 3 1/3 + 2 1/2

2 answers:

skad [1K]2 years ago

7 0

please refer to the document :) and the answer is 5.83

Anvisha [2.4K]2 years ago

6 0

Answer:

$\frac{35}{2} .$

Step-by-step explanation:

$3 \frac{1}{3} + 2 \frac{1}{2} \\ \\ \frac{10}{3} + \frac{5}{2} \\ \\ \frac{10 \times 2 + 5 \times 3}{6} \\ \\ \frac{20 + 15}{6} \\ \\ \frac{35}{6} .$

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The total cost of the smoothie

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4 years ago

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3 years ago

Please help :((((((

Alik [6]

Answer: c)

Step-by-step explanation:

This can be done through trial-and-error. Use the pythagoreas' theorem $a^{2} +b^{2} =c^{2}$ and if the left side of the equation is equal to the right, that is the answer.

(Do take note that c is the longest side.)

a)

$0.07^{2} +2.4^{2} =5.7649$

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Since $2.5^{2} \neq 5.7649$ , a) is wrong.

b)

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Since $34^{2}\neq1189$ , b) is wrong.

c) (answer)

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Since $13^{2} =169$ , c) is correct.

d)

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5 0

2 years ago

find the component equation of the plane which is normal to the vector -2i+5j+k and which contains the point (-10;7;5).

maksim [4K]

Given:

A plane is normal to the vector = -2i+5j+k

It contains the point (-10,7,5).

To find:

The component equation of the plane.

Solution:

The equation of plane is

$a(x-x_0)+b(y-y_0)+c(z-z_0)=0$

Where, $(x_0,y_0,z_0)$ is the point on the plane and $\left< a,b,c\right>$ is normal vector.

Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is

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$-2x-20+5y-35+z-5=0$

$-2x+5y+z-60=0$

$-2x+5y+z=60$

Therefore, the equation of the plane is $-2x+5y+z=60$ .

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3 years ago

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Dafna11 [192]

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3 years ago