Answer: 0.86 of the exam scores are between 68 and 77.99 points
Step-by-step explanation:
Since the set of computer science exam scores are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = computer science exam scores .
µ = mean score
σ = standard deviation
From the information given,
µ = 71.33 points
σ = 3 points
We want to find the proportion of the exam scores are between 68 and 77.99 points. It is expressed as
P(68 ≤ x ≤ 77.99)
For x = 68,
z = (68 - 71.33)/3 = - 1.11
Looking at the normal distribution table, the probability corresponding to the z score is 0.13
For x = 68,
z = (77.99 - 71.33)/3 = 2.22
Looking at the normal distribution table, the probability corresponding to the z score is 0.99
P(68 ≤ x ≤ 77.99) = 0.99 - 0.13 = 0.86
15 ~ 3 - (14~2) just a note, this ~ means the division sign
Answer:
Step-by-step explanation:
We are given that A rose garden can be planted for $4000.
The marginal cost of growing a rose is estimated to $0.30,
Let x be the number of roses
So, Marginal cost of growing x roses = 
Total cost = 
So, Cost function : ---A
Now we are given that the total revenue from selling 500 roses is estimated to $875
So, Marginal revenue = 
Marginal revenue = 
Marginal revenue = 
Marginal revenue for x roses = 
So, Revenue function = ----B
Profit = Revenue - Cost
---C
Now Plot A , B and C on Graph
-- Green
-- Purple
--- Black
Refer the attached graph
