One solution.. what you're describing is two lines that intersect at the common y intercept. This will be the only point that satisfies both equations in the system.
I'm guessing on the make up of the matrices.
First off let's look at [C][F].
[C]=
[F]=
[C][F]=
where each element of [C][F] comes from multiplying a row of [C] with a column of [F].
Example: First element is product of first row and first column.
.
.
.
Now that we have [C][F], we can subtract it from [B], element by element,
[B]-[C][F]=
[B]-[C][F]=
.
.
.
If this is not how the matrices look,please re-state the problem and be more specific about the make up of the matrices (rows x columns).
Here's an example.
[A] is a 2x2 matrix. A=[1,2,3,4].
The assumption is that [A] looks like this,
[A]=
[B] is a 3x2 matrix. B=[5,6,7,8,9,10]
[B]=
Answer: 15
Step-by-step explanation: You do 60/4 to get the answer.
The formula for the equation of a circle is:
(x - h)^2 + (y - k)^2 = r^2
(h, k) is the center.
So the equation would be:
(x + 2)^2 + (y - 3)^2 = 5^2
or
(x + 2)^2 + (y - 3)^2 = 25
